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2 years ago

Stat the law of conservation of momentum

Physics

1 answer:

Alex787 [66]2 years ago

3 0

Answer:

The law has three definitions

Firstly,

The law of conservation of linear momentum states that in any system of colliding objects the total momentum is always conserved provided that there is no net external force acting on the system.

Secondly

If two or more bodies collide in a closed system,the total momentum after the collision is equal to the total momentum before the collision

Thirdly,

The total momentum of an isolated or closed system of colliding bodies remains constant

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a force of 35N is exerted over a cylinder with an area of 5m^2. What pressure,in pascals, will be transmitted in the hydraulic s

gayaneshka [121]

Answer:

<h3>The answer is 7 Pa</h3>

Explanation:

The pressure transmitted in the hydraulic system can be found by using the formula

$p = \frac{f}{a} \\$

f is the force

a is the area

From the question we have

$p = \frac{35}{5} \\$

We have the final answer as

Hope this helps you

8 0

2 years ago

A rotating flywheel has moment of inertia 18.0 kg⋅m^2 for an axis along the axle about which the wheel is rotating. Initially th

timama [110]

Answer:

The rotational kinetic energy takes 0.430 seconds to become half its initial value.

Explanation:

By the Principle of Energy Conservation and the Work-Energy Theorem we know that flywheel slow down due to the action of non-conservative forces (i.e. friction), the energy losses are equal to the change in the rotational kinetic energy. That is:

$\Delta E = K_{1}-K_{2}$ (1)

Where:

$\Delta E$ - Energy losses, measured in joules.

$K_{1}$ , $K_{2}$ - Initial and final rotational kinetic energies, measured in joules.

By definition of rotational kinetic energy, we expand the equation above:

$\Delta E = \frac{1}{2}\cdot I\cdot (\omega_{1}^{2}-\omega_{2}^{2})$ (2)

Where:

$I$ - Moment of inertia of the flywheel, measured in kilograms per square meter.

$\omega_{1}$ , $\omega_{2}$ - Initial and final angular speed, measured in radians per second.

If we know that $K_{1} = 30\,J$ , $K_{2} = 15\,J$ and $I = 18\,kg\cdot m^{2}$ , then the initial angular speed is:

$K_{1} = \frac{1}{2}\cdot I \cdot \omega_{1}^{2}$ (3)

$\omega_{1}=\sqrt{\frac{2\cdot K_{1}}{I} }$

$\omega_{1} = \sqrt{\frac{2\cdot (30\,J)}{18\,kg\cdot m^{2}} }$

$\omega_{1} \approx 1.825\,\frac{rad}{s}$

$\omega_{1}\approx 0.291\,\frac{rev}{s}$

$K_{2} = \frac{1}{2}\cdot I \cdot \omega_{2}^{2}$ (4)

$\omega_{2}=\sqrt{\frac{2\cdot K_{2}}{I} }$

$\omega_{2} = \sqrt{\frac{2\cdot (15\,J)}{18\,kg\cdot m^{2}} }$

$\omega_{2} \approx 1.291\,\frac{rad}{s}$

$\omega_{2} \approx 0.205\,\frac{rev}{s}$

Under the assumption that flywheel is decelerating uniformly, we get that the time taken for the flywheel to slowdown is:

$t = \frac{\omega_{2}-\omega_{1}}{\alpha}$ (5)

If we know that $\omega_{1}\approx 0.291\,\frac{rev}{s}$ , $\omega_{2} \approx 0.205\,\frac{rev}{s}$ and $\alpha = -0.200\,\frac{rev}{s^{2}}$ , then the time needed is:

$t = \frac{0.205\,\frac{rev}{s}-0.291\,\frac{rev}{s}}{-0.200\,\frac{rev}{s^{2}} }$

$t = 0.43\,s$

The rotational kinetic energy takes 0.430 seconds to become half its initial value.

6 0

2 years ago

complete the analogy: 1. speed: velocity;______:______ a. acceleration:velocity b. distance:displacement c. speed:acceleration d

Paraphin [41]

Velocity is the vector,
made up of the scalar speed + direction of speed

b). Displacement is the vector,
made up of the scalar distance + direction of distance

7 0

2 years ago

Read 2 more answers

When you lift a box off the ground gravity opposes your lifting force.

ivolga24 [154]

Answer:

TRUE?

Explanation:

Im not really sure what your question is.

6 0

2 years ago

As an object slides across a rough horizontal

tiny-mole [99]

When the object slides across the rough surface some of its potential energy will be lost to friction.

<h3>Conservation of mechanical energy</h3>

The law of conservation of mechanical energy states that the total mechanical energy of an isolated system is always constant.

M.A = P.E + K.E

When the object slides across the rough surface, some of the potential energy of the object will be converted into kinetic energy while the remaining potential energy will be converted into thermal energy due to frictional force of the rough surface.

P.E = K.E + thermal energy

Learn more about conservation of energy here: brainly.com/question/166559

6 0

1 year ago

Stat the law of conservation of momentum​

Stat the law of conservation of momentum