Answer: 0.18
Explanation:
For the alleles, the percentage distribution of each is 'A' (90% = 0.9)
While 'a' (10% = 0.1)
Hence, 0.9 and 0.1 are the respective frequencies of each allele
Now, apply Hardy-Weinberg Equilibrium equation, where heterozygotes are represented by the 2pq term.
Therefore, the number of heterozygous individuals (Aa) is equal to 2pq which equals
2 × 0.9 × 0.1 = 0.18
Thus, the frequency of heterozygote is 0.18, while the percentage distribution in the population is 18%
Answer:
1- D,C,A,B,E- 2 - B,A,C,D- 3- C,D,B,A.
Explanation:
In DNA, there is a code for the sequence
of three bases for the placement of certain amino acid in a protein chain.<span> The amino acid chain that can be produced by
the DNA base sequence of C-A-A-G-T-T-A-A-A-T-T-A-T-T-G-T-G-A would be based on
the DNA code CAA is valine, GTT is glutamine, AAA is phenylalanine, TTA is asparagine,
TTG is asparagine and TGA is threonine. </span>
We know that frequency of recombination is proportional with the distance between the genes on the chromosome. Therefore when the recombination rate is higher that means the distance between the genes on the chromosome is bigger. If the recombination rate is lower that means the genes are closer to each other on the chromosome. In this case the cross over rate is half the normal rate in the wild-type. That means that on the genetic map the distance between the two genes on the wild type will be twice bigger than the genes of the mutated Drosophila.
