Ask question

Ask question

All categories

2 years ago

14

Which data set is the farthest from a normal distribution? a. 2, 3, 3, 4, 4, 4, 5, 5, 6 b. 3, 4, 5, 6, 6, 7, 7, 7, 8, 8, 9, 10 c

. 0.9, 1.0, 1.0, 1.1, 1.1, 1.1, 1.2, 1.2, 1.3 d. 4, 4, 4, 5, 5, 6, 7, 7, 8, 8, 8 e. 2, 4, 5, 5, 6, 6, 7, 7, 7, 8, 8, 9, 9, 10

1 answer:

Sunny_sXe [5.5K]2 years ago

8 0

Answer: e

Explication: e has the highest distribution with a range starting at 2 and ending with 10

You might be interested in

Please help meeee I have 20 minutes to turn this in

lana66690 [7]

Answer:

RSU = 75.2°

Step-by-step explanation:

this is because:

⇒ RSU = RST + TSU

⇒ RSU = 48 + 27.2

⇒ RSU = 75.2°

Hence proved

6 0

3 years ago

Read 2 more answers

How to simplify the ratio 30ml:45ml

svlad2 [7]

Since 30 and 45 can both be divided by 5, just divided them and is 6:9 and 6 and 9 can be both divided by 3,so the final answer should be 2ml:3ml

4 0

3 years ago

Read 2 more answers

Make an equation to represent the area of a square whose sides are given by the expression x + y

ki77a [65]

Answer:

x^2 + 2xy + y ^2

Step-by-step explanation:

A = a^2

a = x + y

(x + y) + (x + y)

x^2 + xy + xy + y^2

x^2 + 2xy + y ^2

4 0

2 years ago

Composition of functions Find g (f(x)) for the following problems

beks73 [17]

1.

$f(x)=-3x\qquad g(x)=5x-6\\\\g(f(x))=5(-3x)-6=\boxed{-15x-6}$

2.

$f(x)=x-6\qquad g(x)=x^2+6x-2\\\\g(f(x))=(x-6)^2+6(x-6)-2=x^2-12x+36+6x-36-2=\\\\=\boxed{x^2-6x-2}$

3.

$f(x)=4x+3\qquad g(x)=2x^2-x+1\\\\g(f(x))=2(4x+3)^2-(4x+3)+1=2(16x^2+24x+9)-4x-3+1=\\\\=32x^2+48x+18-4x-3+1=\boxed{32x^2+44x+16}$

4.

$f(x)=2x^2\qquad g(x)=8x^2+3x\\\\g(f(x))=8(2x^2)^2+3(2x^2)=8\cdot4x^4+6x^2=\boxed{32x^4+6x^2}$

7 0

2 years ago

What is the value of x

Afina-wow [57]

Answer:

4

Step-by-step explanation:

Sin(30) = LJ/8sqrt(3)

Sin 30 = ½

LJ = 4sqrt(2)

LM = JM = x

x² + x² = (4sqrt(2))²

2x² = 32

x² = 16

x = 4

6 0

3 years ago