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Cloud [144]
3 years ago
13

Help me please please thank

Mathematics
2 answers:
lesantik [10]3 years ago
7 0
14+42+68+79+95= 298/5=59.6
|14-59.6|+|42-59.6|+|68-59.6|+|79-59.6|+|95-59.6|/5=25.28
The answer is 25.3
dsp733 years ago
4 0

Answer:

Step-by-step explanation:

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HELP PLEASE <br><br><br> Simplify.
maksim [4K]
Simplifying
2x + -3(3 * 0.6x + 2.7)

Multiply 3 * 0.6
2x + -3(1.8x + 2.7)

Reorder the terms:
2x + -3(2.7 + 1.8x)
2x + (2.7 * -3 + 1.8x * -3)
2x + (-8.1 + -5.4x)

Reorder the terms:
-8.1 + 2x + -5.4x

Combine like terms: 2x + -5.4x = -3.4x
-8.1 + -3.4x
7 0
3 years ago
Find the original slope and parallel slope !!!!!! Answer correctly !!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!! HELP !!!!!!!
lozanna [386]

Answer:

original slope is 1

parallel slope is 1

Step-by-step explanation:

the slopes of parallel lines are equal

original line rise1/run1, slope is 1

parallel line rise2/run2, slope 2/2=1

3 0
2 years ago
Look at the image and answer the question
BabaBlast [244]

Answer:

e. 1 / 16

f . 1 / 9

Step-by-step explanation:

e.

( 1 / 2 )^4

= 1 / 2^4

= 1 / 16

f.

( 1 / 3 )^2

= 1 / 3^2

= 1 / 9

4 0
3 years ago
Please help ASAP. WILL BRAINLIEST!!!
DaniilM [7]

Answer:

Step-by-step explanation:

9x + 2 + 5 = 14x - 8

9x +7 = 14x -8

7 +8 = 14x - 9x

5x = 15

x = 15/ 5

x = 3

5 0
2 years ago
if one inch represents 14 feet how many inches would you use to make a scale drawing of a building that is 199 feet
gayaneshka [121]

Answer:

14.2 inches

Step-by-step explanation:

Given

1 inch = 14 feet

Required

Find the equivalent of 199 feet

Write out the given expression;

1 inch = 14 feet

Divide both sides by 14

\frac{1\ inch}{14} = \frac{14\ feet}{14}

\frac{1\ inch}{14} = 1\ foot

1 foot = \frac{1}{14}inch

Let x represent the equivalent of 199 feet in inches;

Such that:

x = 199\ feet

x = 199 * 1 foot

Substitute 1 foot = \frac{1}{14}inch

x = 199 * 1 foot becomes

x = 199 * \frac{1}{14} inch

x = \frac{199}{14} inch

x = 14.2142857143 inch

<em>x = 14.2 inches (Approximated)</em>

6 0
3 years ago
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