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2 years ago

A little girl kicks a soccer ball. It goes 10 feet and comes back to her. How is this possible?

1 answer:

8 0

She is standing in front of a wall which is 10 feet away when she kicks the ball and it hits the wall and comes back to her by the virtue of Newton's third Law of motion! She kicks the ball into the air vertically above her and the ball rises to 10 feet and then comes back to her by the virtue of gravity!

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Who is the theorem named after Pythagorean theorem

Illusion [34]

Answer:

Pythagoras of Samos

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

The volume of a soap bubble is 555.4 mm^2 Find the radius and diameter of the soap bubble. Use 3.14 for pi

SashulF [63]

Answer:

radius=11.5

diameter=23

Step-by-step explanation:

The volume of a sphere is V=4/3 Pi r^3

We can use this to solve for the radius.

555.4= 4/3 (3.14)r^3

Solve for r how you would any other equation. Multiply 4/3 and 3.14.

555.4=4.187 r^3

Divide both sides by 4.187

132.65=r^3

To get rid of the ^3, find the cube root of both sides on a calcualtor.

r= 11.5

The diameter is the radius time two.

11.5 (2)=23.

Hope this helps!

Note: When I say both sides, I mean both sides of the = sign.

4 0

2 years ago

Chandra spends 15 minutes doing 4 math problems.She spends the same amount of of time on each problem.How many minutes does she

Serjik [45]

Answer: 3 minutes and 45 seconds

Step-by-step explanation: first, you divide 15 by 4 and that's your answer. Hope this helps!

6 0

2 years ago

A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters

In-s [12.5K]

Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

$\Rightarrow y=\sqrt{x^2+100}$

Differentiating with respect to t

$\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}$

$\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}$

Since the car driving towards the intersection at 13 m/s.

so, $\frac{dx}{dt}=-13$

$\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)$

Now

$\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)$

$=\frac{24\times (-13)}{\sqrt{676}}$

$=\frac{24\times (-13)}{26}$

= -12 m/s

Negative sign denotes the distance between the car and the person decrease.

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

8 0

3 years ago

If Amanda walks at an average speed of 2.72 miles per hour how long will it take her to walk 6.8 miles

defon

Two and a half hours

8 0

3 years ago