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lorasvet [3.4K]
3 years ago
6

Jillian is trying to save water, so she reduces the size of her square grass lawn by 8 feet on each side. The area of the smalle

r lawn is 144 square feet. In the equation
(x – 8)2 = 144, x represents the side measure of the original lawn.

What were the dimensions of the original lawn?

4 feet by 4 feet
8 + feet by 8 +
8 feet by 8 +
20 feet by 20 feet
Mathematics
2 answers:
dsp733 years ago
7 0
<span>The answer is 20 feet by 20 feet. Let's solve the equation: (x – 8)^2 = 144. (x - 8)^2 = 12^2. Since a^2 = b^2 is the same as a = b, then (x - 8)^2 = 12^2 can be simplified to: x - 8 = 12. Now, solve for x. x = 8 + 12. x = 20. Therefore, the dimensions of the original lawn were 20 feet by 20 feet.</span>
vagabundo [1.1K]3 years ago
4 0

Answer:

D

Step-by-step explanation:

20x20

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If P is the orthocenter of △ABC, AB = 13, BF = 9,and FC = 5.6, find each measure &amp; the perimeter of triangle ABC.
harina [27]

Answer:

Perimeter = 38.6

Step-by-step explanation:

Given

A\ B = 13

B\ F = 9

F\ C = 5.6

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To calculate the perimeter of A B C, we sum up the sides of the triangle

i.e.

Perimeter = A B + B\ C + A\ C

AB is given in the question already.

So, we need to calculate B F and F C

To solve for BF, we consider triangle B F C

Using Pythagoras Theorem, we have:

B\ C^2 = B\ F^2 + F\ C^2

Substitute values for BF and FC;

B\ C^2 = 9^2 + 5.6^2

B\ C^2 = 81 + 31.36

B\ C^2 = 112.36

B\ C^2= \sqrt{112.36

B\ C = 10.6

Next, we calculate A C.

To calculate A C, we need to calculate A F, considering triangle B F A

Using Pythagoras Theorem, we have:

A\ B^2 = B\ F^2 + A\ F^2

Substitute values for B F and A B;

13^2 = 9^2 + A\ F^2

169= 81 + A\ F^2

A\ F^2 = 169 - 81

A\ F^2 = 88

A\ F = \sqrt{88

A\ F = 9.4

Since F lies on line A C:

A\ C = A\ F + F\ C

A\ C = 9.4 + 5.6

A\ C = 15.0

Recall that:

Perimeter = A\ B + B\ C + A\ C

Perimeter = 13 + 10.6 + 15.0

Perimeter = 38.6

<em>Hence, the perimeter is 38.6</em>

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