Ask question

Ask question

All categories

2 years ago

5

Two rectangles, A and B are in proportion in ihe ratio 3 : 5. If the area of Rectangle B is 80 cm?, find the area of Rectangle A

?

1 answer:

butalik [34]2 years ago

7 0

Answer:

the area of rectangle A is 133.33 sq cm

Step-by-step explanation:

let us suppose area of rectangle A be x....hence we get ,

3:5=80/x

or,3/5=80/x

or,3x=80*5

or,x=400/3

x=133.3.3

You might be interested in

Solve for x. -3/5x+1/5>7/20

kakasveta [241]

Answer:

Step-by-step explanation:

15 + 720 is 1120

3 0

2 years ago

Which two-dimensional figure could be a cross section of a rectangular pyramid that has been intersected by a plane perpendicula

DanielleElmas [232]

The choices are found elsewhere and the figures would be:
a. rectangleb. trianglec. squared. trapezoid
From the choices, the answer would be option B. A triangle figure would be the cross section when <span>a rectangular pyramid that has been intersected by a plane perpendicular to its base and through</span>its vertex.

7 0

3 years ago

PLEASE HELP WILL MARK BRAINLIEST Write the equation of the line parallel to the given line and passing through the given point.

Naily [24]

The parallel lines have the same slope.

The slope-intercept form: y = mx + b

m - a slope.

We have 6x + y = 4 |subtract 6x from both sides

y = -6x + 4 → m = -6.

The slope-point form:

$y-y_1=m(x-x_1)$

We have m = -6 and (-2, 3).

Substitute:

$y-3=-6(x-(-2))\\\\y-3=-6(x+2)\\\\y-3=(-6)(x)+(-6)(2)\\\\y-3=-6x-12\qquad|+3\\\\y=-6x-9\qquad|+6x\\\\6x+y=-9$

<h3>Answer: 6x + y = -9.</h3>

5 0

3 years ago

Use the normal distribution of SAT critical reading scores for which the mean is 502 and the standard deviation is 116. Assume t

PSYCHO15rus [73]

Answer:

(a) 93.19%

(b) 267.3

Step-by-step explanation:

The population mean and standard deviation are given as 502 and 116 respectively.

Consider, <em>X</em> be the random variable that shows the SAT critical reading score is normally distributed.

(a) The percent of the SAT verbal scores are less than 675 can be calculated as:

$P(X$

Thus, the required percentage is 93.19%

(b)

The number of SAT verbal scores that are expected to be greater than 575 can be calculated as:

$P(X>575)=P(\frac{x-502}{116}>\frac{575-502}{116}\\P(X>575)=P(Z>\frac{575-502}{116})\\P(X>575)=P(Z>0.6293)\\P(X>575)=0.2673$

So,

Out of 1000 randomly selected SAT verbal scores, 1000(0.2673) = 267.3 are expected to have greater than 575.

8 0

3 years ago

Helpppppp!!! PLEASE<br> :((

Ksenya-84 [330]

Answer:

the only one that is a function is B

Step-by-step explanation:

the rest of them have repeating inputs which makes them no functions

7 0

3 years ago