Try finding what the purpose would be of it first before determining the feasibility
Answer:
Just like two boxing athletes competing in a match, the boxer engine works similarly. The horizontally positioned pistons inside the engine create a better balance with their side-to-side motion as compared to V-shaped engines.
Explanation:
Answer:
8.62m/s²
Explanation:
the particle is experiencing both translational and circular motion
v=4t²
=
=8t
at t=1s,
=8(1)=8m/s²
= ![\frac{v^{2} }{r}](https://tex.z-dn.net/?f=%5Cfrac%7Bv%5E%7B2%7D%20%7D%7Br%7D)
at t=1, v= 4(1)² = 4m/s
=4²/5
=3.2m/s²
∴ magnitude of total acceleration, a
a=![\sqrt{a_{t} ^{2} + a_{c} {2} }](https://tex.z-dn.net/?f=%5Csqrt%7Ba_%7Bt%7D%20%5E%7B2%7D%20%2B%20a_%7Bc%7D%20%7B2%7D%20%7D)
a=![\sqrt{8^{2} +3.2^{2} }](https://tex.z-dn.net/?f=%5Csqrt%7B8%5E%7B2%7D%20%2B3.2%5E%7B2%7D%20%20%7D)
a=![\sqrt{64+10.24}](https://tex.z-dn.net/?f=%5Csqrt%7B64%2B10.24%7D)
a=![\sqrt{74.24}](https://tex.z-dn.net/?f=%5Csqrt%7B74.24%7D)
a=8.62m/s²
Answer:
Hook's law holds good up to. A elastic limit. B. plastic limit. C.yield point. D.Breaking point
Given Information:
Balanced Y-Y three phase circuit
Phase Voltage = Van = 120 < 10° V
Load Impedance = Zy = 20 +j15 Ω = 25 < 36.86° Ω
Required Information:
Load Voltages = Vab, Vbc, Vca = ?
Line currents = Ia, Ib, Ic = ?
Answer:
Vab = 208 < 40°
Vbc = 208 < -80°
Vca = 208 < 160°
Ia = 4.8 < -26.86°
Ib = 4.8 < -146.86°
Ic = 4.8 < 93.14°
Explanation:
Since it is balanced 3 phase system, all phases have equal magnitude and 120° phase shift
Van = 120 < 10° V
Vbn = 120 < -110° V
Vcn = 120 < 130° V
In a Y connected system, the phase voltage and line voltage are related as
Vab =
(Van) <+30°
Vab =
*120<10°+30°
Vab = 208 < 40°
Vbc = 208 < -80°
Vca = 208 < 160°
In a Y connected circuit, Iphase = Iline
Ia = Van/Zy
Ia = 120 < 10°/25 < 36.86°
Ia = 4.8 < -26.86°
Ib = 4.8 < -146.86°
Ic = 4.8 < 93.14°