Answer:
248.756 mV
49.7265 µA
Explanation:
The Thevenin equivalent source at one terminal of the bridge is ...
voltage: (100 V)(1000/(1000 +1000) = 50 V
impedance: 1000 || 1000 = (1000)(1000)/(1000 +1000) = 500 Ω
The Thevenin equivalent source at the other terminal of the bridge is ...
voltage = (100 V)(1010/(1000 +1010) = 100(101/201) ≈ 50 50/201 V
impedance: 1000 || 1010 = (1000)(1010)/(1000 +1010) = 502 98/201 Ω
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The open-circuit voltage is the difference between these terminal voltages:
(50 50/201) -(50) = 50/201 V ≈ 0.248756 V . . . . open-circuit voltage
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The current that would flow is given by the open-circuit voltage divided by the sum of the source resistance and the load resistance:
(50/201 V)/(500 +502 98/201 +4000) = 1/20110 A ≈ 49.7265 µA
Answer:
An emergency kit
Explanation:
The reason I say this is because:
A first aid kit can aid you if you have..
Scars
Cuts
Bruises
So, i would say that The first aid kit is the life line.
Answer:
<em>v</em><em> </em>= T/(2R)
Explanation:
Given
R = radius
T = strength
From Biot - Savart Law
d<em>v</em> = (T/4π)* (d<em>l</em> x <em>r</em>)/r³
Velocity induced at center
<em>v </em>= ∫ (T/4π)* (d<em>l</em> x <em>r</em>)/r³
⇒ <em>v </em>= ∫ (T/4π)* (d<em>l</em> x <em>R</em>)/R³ (<em>k</em>) <em>k</em><em>:</em> unit vector perpendicular to plane of loop
⇒ <em>v </em>= (T/4π)(1/R²) ∫ dl
If l ∈ (0, 2πR)
⇒ <em>v </em>= (T/4π)(1/R²)(2πR) (<em>k</em>) ⇒ <em>v </em>= T/(2R) (<em>k</em>)
Answer:
Explanation:
Work, U, is equal to the force times the distance:
U = F · r
Force needed to lift the weight, is equal to the weight: F = W = m · g
so:
U = m · g · r
= 20.4kg · 9.81
· 1.50m
= 35.316 
= 35.316 W
Answer:
The diameter increases
Explanation:
The expansion in the metal is uniform in every dimension