Answer:
a) 46.76 Lsun
b) 2187 Lsun
c ) You can easily estimate the luminosity of a 3-solar massed giant star because its luminosity is close to the luminosity of the sun
Explanation:
To estimate the luminosity of a celestial body in terms of solar luminosity we use the expression below
=
a) Estimate the luminosity of a 3 solar mass main sequence star
=
Hence ; L(luminosity of a 3 solar mass star ) = 46.76 Lsun
b) Estimate the luminosity of a 9-solar-mass main sequence star
=
hence L( luminosity of a 9-solar mass star ) = 2187 Lsun
c ) You can easily estimate the luminosity of a 3-solar massed giant star because its luminosity is close to the luminosity of the sun
Answer:
Explanation:
= 113.27 g - 49.31 g = 63.96 g
= 100.06 g - 49.31 g = 50.75
Moisture /water content, w = =
= 0.26 = 26%
Void ratio = water content X specific gravity of solid
= 0.26 X 2.80 =0.728
Answer:
gauge pressure is 133 kPa
Explanation:
given data
initial temperature T1 = 27°C = 300 K
gauge pressure = 300 kPa = 300 × 10³ Pa
atmospheric pressure = 1 atm
final temperature T2 = 77°C = 350 K
to find out
final pressure
solution
we know that gauge pressure is = absolute pressure - atmospheric pressure so
P (gauge ) = 300 × 10³ Pa - 1 × Pa
P (gauge ) = 2 × Pa
so from idea gas equation
................1
so
P2 = 2.33 × Pa
so gauge pressure = absolute pressure - atmospheric pressure
gauge pressure = 2.33 × - 1.0 ×
gauge pressure = 1.33 × Pa
so gauge pressure is 133 kPa
Answer:
Following are the conversion to this question:
Explanation:
In point (a):
In point (b):
In point (c):
Symbols of Base 25 are as follows: