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Alexxx [7]
3 years ago
13

What are the relative volume requirements for a CM reactor compared to a PF reactor if first-order kinetics apply and treatment

efficiencies of 50%, 75%, 90%, 95%, and 99% are required?
Engineering
1 answer:
Tanzania [10]3 years ago
6 0

Answer:

look it up

Explanation:

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A solid round bar with a diameter of 2.32 in has a groove cut to a diameter of 2.09 in, with a radius of 0.117 in. The bar is no
Alenkinab [10]

Answer:

nf=1.11 (Goodman criterion)

ny=2.41 (factor of safety for fatigue)

Explanation:

From the table A-20 Deterministic ASTM minimum tensile and yield strengths for HR and CD steels, we have approximately:

Sut=120 kpsi

Sy=66 kpsi

Due Sut<1400 Mpa, the endurance limit is:

Se=0.5Sut=0.5*120=60 kpsi

The surface condition modification factor is:

ka=a(Sut)^{b}=2.7(120)^{-0.265} =0.759

The effective diameter is:

de=0.37d=0.37*2.09=0.7733 in

The size factor is:

kb=0.879de^{-0.107} =0.879(0.7733)^{-0.107} =0.9

The endurance limit at critical location is:

See=ka*kb*kc*kd*kd*ke*kf*Se=0.759*0.9*1*60=40.986 kpsi

\frac{D}{d}=\frac{2.32}{2.09}  =1.11\\\frac{r}{d}=\frac{0.117}{2.09}  =0.056

From Figure A-15-15 chart, the Kf = 2.1

The notch sensitivity is:

\sqrt{a}=0.246-3.08(10^{-3})Sut+1.51(10^{-5})Sut^{2}-2.67(10^{-8})Sut^{3}

\sqrt{a}=0.246-3.08(10^{-3})(120)+1.51(10^{-5})(120^{2})-2.67(10^{-8})(120^{3})=0.048

q=\frac{1}{1+\frac{\sqrt{a} }{\sqrt{r} } }=\frac{1}{1+\frac{0.048}{\sqrt{0.117} } }=0.877

The fatigue stress is:

Kf=1+q(Kt-1)=1+0.877(2.1-1)=1.96

The moment of inertia is:

I=\frac{\pi }{64} d^{4}=\frac{\pi }{64}  (2.09^{4})=0.936 in^{4}

The maximum stress is:

omax=\frac{M*c}{I}=\frac{25000*\frac{2.09}{2} }{0.936}  =27911.32 psi=27.911 kpsi

The mean stress is:

om=Kf\frac{omax+omin}{2} =1.96\frac{27.911+0}{2}=27.35 kpsi

The alternate stress is:

oa=Kf|\frac{omax-omin}{2}|=27.35 kpsi

The fatigue factor using Goodman is:

\frac{1}{nf}=\frac{oa}{See}+\frac{om}{Sut}\\\frac{1}{nf}=\frac{27.35}{40.986}+\frac{27.35}{120}

nf=1.11

the factor of safety is:

ny=\frac{Sy}{omax}=\frac{66}{27.35}  =2.41

4 0
4 years ago
What is clearance? What is backlash? What is interference? Explain briefly.
Anton [14]

Explanation:

Clearance:

For easy matching  and dis matching  of  hole and  shaft we use size of hole little bit more than the size of shaft and this difference in size is called clearance.

Backlash:

  It is the clearance between the two mating gear to avoids failure of gears.Actually when temperature of gears increases then at the same time the size of gear also increases ,due this there is a possibility foe jamming of gears so to avoids this backlash is provides.

Interference:

  When two gears are matting then addendum of one gear inters into the deddendum of another gear and due to this gears get jam .This phenomenon is called interference.

5 0
3 years ago
The I26 profile beam is supported and loaded as in the figure. It is required to calculate the vertical movement of the free end
jarptica [38.1K]

Answer:

...

Explanation:

...

6 0
3 years ago
A 400 kg machine is placed at the mid-span of a 3.2-m simply supported steel (E = 200 x 10^9 N/m^2) beam. The machine is observe
Alenkinab [10]

Answer:

moment of inertia = 4.662 * 10^6 mm^4

Explanation:

Given data :

Mass of machine = 400 kg = 400 * 9.81 = 3924 N

length of span = 3.2 m

E = 200 * 10^9 N/m^2

frequency = 9.3 Hz

Wm ( angular frequency ) = 2 \pi f = 58.434 rad/secs

also Wm = \sqrt{\frac{g}{t} }  ------- EQUATION 1

g = 9.81

deflection of simply supported beam

t = \frac{wl^3}{48EI}

insert the value of t into equation 1

Wm^2 = \frac{g*48*E*I}{WL^3}   make I the subject of the equation

I ( Moment of inertia about the neutral axis ) = \frac{WL^3* Wn^2}{48*g*E}

I = \frac{3924*3.2^3*58.434^2}{48*9.81*200*10^9}  = 4.662 * 10^6 mm^4

6 0
3 years ago
When _____ ,the lithium ions are removed from the_____ and added into the _____
bezimeni [28]

Answer:

b. Discharging; anode; cathode

Explanation:

When discharging , it means the battery is producing a flow electric current, the lithium ions are released from the  anode to the cathode which generates the flow of electrons from one side to another. When charging Lithium ions are released by the cathode and received by the anode.

8 0
3 years ago
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