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2 years ago

Solve this:

Mathematics

1 answer:

Alex73 [517]2 years ago

7 0

Answer:

i = 17 Years old
ii = 25 years

Step-by-step explanation:

i = 12 + 5 =17

ii = his son was born when he was 9, hes 12 now, so his sons 3. In 5 years time his sons 8 and hes 17, 8+17= 25

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Choose the correct description of the graph of the compound inequality shown below;

baherus [9]

Answer: C Hope it's helpful

3 0

3 years ago

F/13 = 6.2 what is the value of f

nekit [7.7K]

Answer:

The value of f is 80.6.

Step-by-step explanation:

We are given the equation and asked to solve for f.

If we are given a fraction with a variable in the numerator, we can multiply both sides of the equation by the denominator to isolate it.

For example, if you look at this equation:

$\displaystyle\frac{a}{26}=17.9$

We can multiply both sides by 26 to get the a by itself so the equation can be solved.

$\displaystyle26\times\frac{a}{26}=17.9\times26\\\\a = 465.4$

Therefore, we can apply this same technique to the equation $\frac{f}{13}=6.2.$

$\displaystyle\frac{f}{13}=6.2\\\\13\times\frac{f}{13}=6.2\times13\\\\f = 80.6\ \text{or} \ \frac{403}{5}$

Therefore, the value of f is 80.6.

5 0

3 years ago

Read 2 more answers

Please help ,this is the third time that i ha posted thi question

klio [65]

The answer is 14+8.125π units².

3 0

3 years ago

A cliff diver jumps from a cliff that is 96 feet above the water. His jump can be modeled by a quadratic equation, h= -16t(expon

ladessa [460]

Answer:

The diver will take 2.449 seconds to enter the water.

Step-by-step explanation:

We have been given that quadratic equation for the diver jumps is

$h=-16t^2+96$

We have to find the time taken for the diver to enter the water. When the diver enters the water, the height becomes zero.

$0=-16t^2+96\\\\16t^2=96\\\\t^2=6\\\\t=\sqrt6\\\\t=2.449\text{ seconds}$

Therefore, the diver will take 2.449 seconds to enter the water.

4 0

3 years ago

2 tan 30°<br>II<br>1 + tan- 300

shusha [124]

Question:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$

Answer:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= sin(60^{\circ})$

Step-by-step explanation:

Given

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$

Required

Simplify

In trigonometry:

$tan(30^{\circ}) = \frac{1}{\sqrt{3}}$

So, the expression becomes:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2 * \frac{1}{\sqrt{3}}}{1 + (\frac{1}{\sqrt{3}})^2}$

Simplify the denominator

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2 * \frac{1}{\sqrt{3}}}{1 + \frac{1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{1 + \frac{1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{ \frac{3+1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{ \frac{4}{3}}$

Express the fraction as:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2}{\sqrt 3} / \frac{4}{3}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2}{\sqrt 3} * \frac{3}{4}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{1}{\sqrt 3} * \frac{3}{2}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3}{2\sqrt 3}$

Rationalize

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3}{2\sqrt 3} * \frac{\sqrt{3}}{\sqrt{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3\sqrt{3}}{2* 3}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\sqrt{3}}{2}$

In trigonometry:

$sin(60^{\circ}) = \frac{\sqrt{3}}{2}$

Hence:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= sin(60^{\circ})$

3 0

3 years ago