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iris [78.8K]
2 years ago
6

The expression c + 0.07c can be used to find the total cost of an item with 7% sales tax, where c is the cost of the item. Use t

he expression to find the total cost of an item that is $25.
Mathematics
1 answer:
Nataly_w [17]2 years ago
3 0

The total cost of the item at the value of $25 and a tax of 7% is $26.75

<h3>Total Cost </h3>

Given Data

  • Tax = 7%
  • Cost of item c = $25

We have the given expression to find the total cost which is

Total = c + 0.07c

Substituting our given data into the expression we have

Total = 25 + 0.07*25

Total = 25 + 1.75

Total = $26.75

Learn more about total cost here:

brainly.com/question/25109150

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The hardcover version of a book weighs twice as much as its paperback version. The hardcover book and the paperback together wei
jasenka [17]

I think  H=P*2/4.2 could work corrext me if im wrong please


5 0
3 years ago
Read 2 more answers
Simplify completely quantity of x squared plus 7 x minus 30 all over quantity of x plus 10. x2 + 4 x2 ? 4 x ? 3 x + 3
GalinKa [24]

This looks like: \frac{x^2+7x-30}{x+10}

To solve this problem, you'll want to use the AC method to factor x^2+7x-30.

After factoring your expression will look like this:

\frac{(x-3)(x+10)}{x+10}

Cancel out the x+10 because they are common factors, so you are just left with the simple x-3.

Answer is:

x - 3

4 0
2 years ago
Read 2 more answers
Why might you want to round to the nearest hundred rather than the nesrest ten
Ipatiy [6.2K]
I would want to round to the nearest hundred place rather than the nearest tens place because if you round to the nearest hundred place then your answer would be closer to the original answer.
6 0
3 years ago
Find the interval(s) where the function is increasing and the interval(s) where it is decreasing. (Enter your answers using inte
Mashcka [7]

Answer:

f'(x) > 0 on (-\infty ,\frac{1}{e}) and f'(x)<0 on(\frac{1}{e},\infty)

Step-by-step explanation:

1) To find and interval where any given function is increasing, the first derivative of its function must be greater than zero:

f'(x)>0

To find its decreasing interval :

f'(x)

2) Then let's find the critical point of this function:

f'(x)=\frac{\mathrm{d} }{\mathrm{d} x}[6-2^{2x}]=\frac{\mathrm{d} }{\mathrm{d}x}[6]-\frac{\mathrm{d}}{\mathrm{d}x}[2^{2x}]=0-[ln(2)*2^{2x}*\frac{\mathrm{d}}{\mathrm{d}x}[2x]=-ln(2)*2^{2x}*2=-ln2*2^{2x+1\Rightarrow }f'(x)=-ln(2)*2^{2x}*2\\-ln(2)*2^{2x+1}=-2x^{2x}(ln(x)+1)=0

2.2 Solving for x this equation, this will lead us to one critical point since x'  is not defined for Real set, and x''=\frac{1}{e}≈0.37 for e≈2.72

x^{2x}=0 \ni \mathbb{R}\\(ln(x)+1)=0\Rightarrow ln(x)=-1\Rightarrow x=e^{-1}\Rightarrow x\approx 2.72^{-1}x\approx 0.37

3) Finally, check it out the critical point, i.e. f'(x) >0 and below f'(x)<0.

8 0
3 years ago
Points X and Z are on a number line, and point Y partitions
abruzzese [7]

Answer:

The coordinate of Z is 13.36.

Step-by-step explanation:

According to the statement, we have the following information:

\frac{XY}{XZ} = \frac{5}{12} (1)

\frac{YZ}{XZ} = \frac{7}{12} (2)

X = 0.4 (3)

Y = 5.8 (4)

From (2), we have the following expression:

YZ = \frac{7}{12}\cdot XZ

Y-Z =\frac{7}{12}\cdot (X-Z)

Y - Z = \frac{7}{12}\cdot X -\frac{7}{12}\cdot Z

Y-\frac{7}{12}\cdot X = Z-\frac{7}{12}\cdot Z

\frac{5}{12}\cdot Z = Y-\frac{7}{12}\cdot X

5\cdot Z = 12\cdot Y-7\cdot X

Z = \frac{12}{5}\cdot Y-\frac{7}{5}\cdot X (5)

If we know that Y = 5.8 and X = 0.4, then the coordinate of Z is:

Z = \frac{12}{5}\cdot (5.8)-\frac{7}{5}\cdot (0.4)

Z = 13.36

The coordinate of Z is 13.36.

6 0
2 years ago
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