You get a complex fraction and you then have to "copy, dot, flop"
For example, (1/2)/5
To solve this, you would change it to 1/2 x 1/5 to get .1
You wanna do 96 dived by 23 but if you do 24 instead the answer should be 4
The answer is 0. This is because of the proportion of the two
Answer:
<h2>11</h2>
Step-by-step explanation:
Given h(t) = t²+t+ 12 and k(t) = √t-1, we are to find k(k.h)(10)
k{h(t)} = k{ t²+t+ 12}
Since k(t)= √t-1, we will replace the variable t in the function with t²+t+ 12
k(h(t)) = √{(t²+t+ 12)-1}
k(h(t)) = √t²+t+12-1
k(h(t)) = √t²+t+11
Substituting t = 10 into the resulting function;
k(h(10)) = √(10)²+(10)+11
k(h(10)) = √100+10+11
k(h(10)) = √121
<em>k(h(10))= 11</em>
<em></em>
<em>hence the value of (k compose h) (10) is 11</em>
A. Because it is less than 1 times 111.