Answer:
c^6
Step-by-step explanation:
c^5*c^1=c^5+1=c^6
Answer:
hbiygbygby8gbygbygb 86tb87tb8ygb uygb8ytvbtygb 8yg
Step-by-step explanation:
noijnihv ygfhjnb 76rtgvtgby v7btg cv7tf6gy 746d5tfvygbhj 6rft7gvy
5x3=15. 15+6=21. The answer would be 3
In order for the ball to be used in the game, it must be able to meet the minimum and maximum weight requirements. These are the limits of the weight of the ball. If it exceeds the maximum limit of 16 ounces or below the minimum limit of 14 ounces, the ball will not be approved.
So, by adding 1.5 ounces, that would mean that the initial weight of the ball did not reach the minimum limit. The initial weight of the ball, denoted as x, have two possible values. The first value is the initial weight plus added with 1.5 ounces would reach 14 ounces.
x + 1.5 = 14
x = 12.5 ounces
The other scenario is when the initial weight is added to reach the maximum requirement of 16 ounces
x + 1.5 = 16
x = 14.5 ounces
From both answer, we could conclude that the initial weight has to be 12.5 ounces. If the initial weight were 14.5 ounces to begin with, there should be no need for air. It cans till be approved to be used.
It is given that John wants to find the center of a wall so he can hang a picture. So, John measures the wall and <u>determines</u> it is 65.25 inches wide. Since John has determined that the wall measures a particular amount that means that John has <u>quantified</u> the width of the wall, which in this case comes out to be 65.25 inches.
Again, this is a single number. This means that the width of the wall is a <u>discrete</u> quantity.
Thus, 65.25 inches or 65.25" is a Quantitative and Discrete type of data. Thus, out of the given options, the first option is the correct one.
