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Vedmedyk [2.9K]
2 years ago
9

You start out with 800 moles of a radioactive substance. After 24 hours, 100 moles remain. What is the half-life of the substanc

e in hours?
Question 1 options:

6 hours


12 hours


4 hours


8 hours
Chemistry
1 answer:
Nookie1986 [14]2 years ago
3 0

The half life of the substance is 8 hours , Option D is the correct answer.

<h3></h3>

What is Half Life ?

Half-life is the time required by an unstable element  to reduce to half of its initial value.

The term is commonly used in nuclear physics.

The formula is

\rm N(t) = \; N_{0} \;(\dfrac{1}{2} )^{\frac{t}{t_{1/2} } }

N(t)     =    quantity of the substance remaining

N ₀      =    initial quantity of the substance

t    =  time elapsed

\rm t_{1/2}    =    half life of the substance

The data given in the question is N ₀ = 800 moles , N(t)= 100 , t= 24 hours

\rm t_{1/2} =\; ?

Substituting values in the equation

\rm 100 = \; 800 \;(\dfrac{1}{2} )^{\frac{24}{t_{1/2} } }

\rm \dfrac{100}{800}  =  \;(\dfrac{1}{2} )^{\frac{24}{t_{1/2} } }\\\\\rm \dfrac{1}{8}  =  \;(\dfrac{1}{2} )^{\frac{24}{t_{1/2} } }\\\\\rm (\dfrac{1}{2})^{3}  =  \;(\dfrac{1}{2} )^{\frac{24}{t_{1/2} } }\\\\\rm 3=\dfrac{24}{t_{1/2} }\\\\t_{1/2}= \dfrac{24}{3}\\\\t_{1/2} = 8 hours

Therefore half life of the substance is 8 hours , Option D is the correct answer.

To know more about Half Life

brainly.com/question/24710827

#SPJ2

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To calculate the pH of a solution, we first need to find the concentration of hydronium ions in the solution. Since KOH is a strong base, it dissociates completely in water to produce hydroxide ions (OH-) and potassium ions (K+).

The concentration of hydronium ions in a solution of KOH can be calculated using the concentration of hydroxide ions and the equilibrium constant for water, which is equal to 1.00 x 10^-14 at 25 degrees Celsius.

The concentration of hydroxide ions in a 0.160 M solution of KOH is equal to the concentration of KOH, which is 0.160 M. The concentration of hydronium ions in the solution can be calculated using the equation below:

[H3O+] = (1.00 x 10^-14) / [OH-]

Substituting the concentration of hydroxide ions into the equation above, we get:

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To calculate the pH of the solution, we need to take the negative logarithm of the concentration of hydronium ions. This can be done using the equation below:

pH = -log([H3O+])

Substituting the concentration of hydronium ions into the equation above, we get:

pH = -log(6.25 x 10^-13) = 12.20

The pH of a 0.160 M solution of KOH is 12.20.

To calculate the pOH of a solution, we first need to find the concentration of hydroxide ions in the solution. Since we already calculated this value above, we can simply use the concentration of hydroxide ions we found earlier: 0.160 M.

To calculate the pOH of the solution, we need to take the negative logarithm of the concentration of hydroxide ions. This can be done using the equation below:

pOH = -log([OH-])

Substituting the concentration of hydroxide ions into the equation above, we get:

pOH = -log(0.160 M) = 1.80

The pOH of a 0.160 M solution of KOH is 1.80.

Learn more about pH:
brainly.com/question/28864035

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