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Tatiana [17]
3 years ago
12

What is is a simple definition of reduction?

Chemistry
1 answer:
alexandr402 [8]3 years ago
3 0

having a lesser value by a process of depletion

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C3H8 + xO2 &gt; 3CO2 + yH2O<br> which value of x and y balance the equations
Gelneren [198K]

Answer:

x = 5 and y =4

Explanation:

An alkane is a hydrocarbon of general molecular formula CnH2n+2. The general formula for balancing the combustion equation of any alkane is;

CnH2n+2 + 3n+1/2O2 ------> nCO2 + (n+1) H2O

Where n is the number of carbon atoms in the alkane.

In C3H8 , n=3 so;

C3H2(3)+2 + 3(3)+1/2O2 ------> 3CO2 + (3+1) H2O

Then;

C3H8 + 5O2  ------> 3CO2 + 4H2O

Therefore;

x = 5 and y =4

8 0
2 years ago
Which term best indicates the average mass of an atom of an element?
Firdavs [7]
The answer is the atomic mass.
8 0
3 years ago
Read 2 more answers
Draw the major organic product for the reaction of 1-phenylpropan-1-one with the provided phosphonium ylide.
prohojiy [21]

Answer:

2-methylene propylbenzene

Explanation:

The Wittig Reaction is a reaction that converts aldehydes and ketones into alkenes through reaction with a phosphorus ylide.

The ketone in this case is 1-phenylpropan-1-one. The provided phosphonium ylide is shown in the image attached. The reaction involves;

i) alkylation  

ii) addition

The product of the major organic product of the reaction is 2-methylene propylbenzene.

4 0
2 years ago
WILL MARK BRAINLIEST please
astra-53 [7]

Answer:

C is the only reasonable answer.. but this is 6th grade science and I'm in 7th, so I'm pretty sure I'm right

5 0
3 years ago
determine the freezing point depression of a solution that contains 30.7 g glycerin (c3h8o3, molar mass
Blababa [14]

The freezing point depression of a solution containing 30.7 g of glycerin  is  calculated as -1.65°C

Equating :

It is given that,

Given mass of glycerin is = 30.7 grams (Solute)

Volume of water = 376 mL

K_{f}or molar -freezing-depression point is = 1.86°C/m

Molar mass of glycerin = 92.09 g/mole

Now, to work out the value, the mass of water should be known. Thus, to calculate, the formula used will be:

Mass = Density X Volume

Mass = 1.0 g/mL X 376 mL

Mass = 376 g or 0.376 Kg

Using the formula of melting point depression, the equation becomes:

             ΔT_{f} = i ×K_{f} ×m

T⁰-T_{s}  = i *K_{f} *\frac{mass of glycerin}{molar mass of glycerin * mass of water     in     kg}

in which,

ΔT_{f} = change in freezing point

ΔT_{s} = freezing point of solution that has to be find

ΔT° = freezing point of water ()

Since, glycerin is a non-electrolyte, the Van't Hoff factor will be 1.

Substituting the values in the above equation:

0⁰C₋T_{s} = 1 ×1.86°C/m ×\frac{30.7}{92.09g/mol * 0.376kg}

T_{s} = -1.65°C

Thus, the freezing point depression of a solution is  -1.65°C

<h2 />

Freezing point depression

Freezing point depression is a colligative property observed in solutions that results from the introduction of solute molecules to a solvent. The freezing points of solutions are all less than that of the pure solvent and is directly proportional to the molality of the solute

Is melting point elevation or depression?

Boiling point elevation is that the raising of a solvent's boiling point due to the addition of a solute. Similarly, melting point depression is the lowering of a solvent's freezing point due to the addition of a solute. In fact, because the boiling point of a solvent increases, its melting point decreases

Learn more about freezing point depression :

brainly.com/question/26525184

#SPJ4

8 0
8 months ago
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