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3 years ago

An easy question all wrong or unhelpful or no-work answers will be reported.

1 answer:

6 0

Elimination:

7x - 3y = 20
5x + 3y = 16
(add)
12x = 36
÷ 12
x = 3

(5 × 3) + 3y = 16
15 + 3y = 16
- 15
3y = 1
÷ 3
y = 1/3

Substitution:

5x + 3y = 16
- 3y
5x = 16 - 3y
÷ 5
x = 3.2 - 0.6y

5(3.2 - 0.6y) + 3y = 16
16 - 3y + 3y = 16
16 = 16
- 16
6y = 0
÷ 6
y = 0

Sorry the substitution messed up for some reason, I'll fix it after I've answered the other question

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3 years ago

If 5 sips +4 gulps = 1 glass and 13 sips +7 gulps = 2 glasses, how many sips equal a gulp?

nataly862011 [7]

Answer:

3 sips equal a gulp

Step-by-step explanation:

we have

$5sips+4gulps=1glass$ ----> equation A

$13sips+7gulps=2glass$

Divide by 2 both sides

$6.5sips+3.5gulps=1glass$ ----> equation B

equate equation A and equation B

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3 years ago

A conditional statement is logically equivalent to a biconditional statement. True False pls help i have a test and i was absent

andreyandreev [35.5K]

Answer:

false.

Step-by-step explanation:

A conditional statement is something like:

If P, then Q.

This means that if a given proposition P is true, then another proposition Q is also true.

An example of this is:

P = its raining

Q = there are clouds in the sky.

So the conditional statement is

If its raining, then there are clouds in the sky.

A biconditional statement is:

P if and only if Q.

This means that P is only true if Q is true, and Q is only true if P is true.

So, using the previous propositions we get:

Its raining if and only if there are clouds in the sky.

This statement is false, because is possible to have clouds in the sky and not rain.

(this statement implies that if there are clouds in the sky, there should be rain)

Then we could see that for the same propositions, the conditional statement is true and the biconditional statement is false.

Then these statements are not logically equivalent.

The statement is false.

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3 years ago

Need help please :( What is the second term of (s+v)^5?

Citrus2011 [14]

First compute the coefficient like this:
$C_5^1=\frac{5!}{1!(5-1)!}=\frac{5!}{4!}=\frac{5\times4!}{4!}$
Simplifying the fraction over 4! we get:
$C_5^1=5$
and the variables are $s^4v$ . So answer $5s^4v$ .

The correct answer is C then.

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3 years ago