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kodGreya [7K]
3 years ago
11

HELP ASAP!!!!!!!!!!!!!!!!!!! PLEASE!!

Mathematics
1 answer:
vekshin13 years ago
3 0

Answer:

yes/ In 4 years, Dinah will have gained $102.00.

Step-by-step explanation:

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20 POINTS! Please help
Marysya12 [62]

The complete square will be  (x-3)^{2} = 3

Step-by-step explanation:

Given,

2x^{2} -12x+12=0

or, x^{2} -6x+6=0 [ by eliminating 2 from both the sides]

To make it square

x^{2} -6x+6=0

or, x^{2} -2xX3+9-9+6=0 [ (a+b)^{2}=a^{2} +2ab+b^{2}

or, (x-3)^{2} = 9-6

or, (x-3)^{2} = 3

Hence the correct option is B

3 0
3 years ago
Pls Answer! Will give brainliest. Khanna earns a annual salary of $33,000. Her federal income tax bracket is 20%. She also must
maks197457 [2]

Answer: $3,581

Step-by-step explanation:

As she plans to save from her net income, we have to find the net income first:

= Net income - Federal taxes - Social and Medicare taxes

= 33,000 - (33,000 * 20%) - (33,000 * 7.65%)

= $23,875.50

The savings will be:

= Net income * Savings percentage

= 23,875.50 * 15%

= $3,581.325

= $3,581

8 0
2 years ago
Will mark brainliest and rate 5/5
Kay [80]

B OR D IT WAS confusing.

Step-by-step explanation:

I tried different equations multiple ways I'm pretty sure I did it wrong

5 0
2 years ago
Read 2 more answers
Casey likes to run. She runs an additional 1/4 mile each day. On the last day, she ran 1 1/4 miles. If she ran 1/2 mile her firs
Salsk061 [2.6K]
Three days,
1 1/4 = 5/4  
1/2= 2/4
2/4+1/4= 3/4 the first day
5/4-3/4= 2/4 
2/4 = 1/4 and 1/4 = two days
the first day+ two days= 3 days
3 0
3 years ago
Read 2 more answers
For each function below, determine whether or not the function is injective and whether or not the function is surjective. (You
Harlamova29_29 [7]

Answer: First, injective means that for every y, there is only one x such f(x) = y, and surjective means that if f is a function that goes from the set {x} to the set {y}, for every element y in the codomain there is at least one element x in the domain such f(x) = y

(a) f:R----> + R given by f(x) = x2 (i guess you written x^{2})

The function is not injective, because f(-2) = f(2), and is surjective, because the codomain is +R, and x^{2} is always a positive real number.

(b) f:N----> + N given by f(n) = n2  (i guess you written n^{2})

As the naturals have no negative numbers, in this case the function is injective, but isn't surjective, because there is no number that when squared is equal to 5, for example.

(c) f: Zx Z → Z given by f(n, k) = n +k:

here the domain is of the form (n,k) and the function is n +k, so the numbers (z,w) and (w,z) return the same value when evaluated in f, then f is not injective. And is easy to see that f is surjective, because in the sum you can reach al the integers on the codomain.

3 0
3 years ago
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