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3 years ago

4/5+×=13/5 how do I solve this problem

1 answer:

4 0

Subtract 4/5 from each side.
You get x=9/5
For future problems like this, use the inverse operations.
Inverse operations: (Addition, subtraction) (Multiply, divide)
Like if it is 5x=25, divide by 5.
x=5
For this x=9/5 though

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Question 2 An exponential model y = a.6 passes through the points (0,9) and (3,243). What are the values of a and b?

weqwewe [10]

Answer:

a = 9, b = 3

Step-by-step explanation:

The exponential function is

y = a $b^{x}$

Find a and b by using the points it passes through

Using (0, 9 ) then

9 = a $b^{0}$ ( $b^{0}$ = 1 )

a = 9

y = 9 $b^{x}$

Using (3, 243 ) then

243 = 9b³ ( divide both sides by 9 )

27 = b³ ( take the cube root of both sides )

b = $\sqrt[3]{27}$ = 3

y = 9 $(3)^{x}$ ← exponential equation

8 0

3 years ago

Matrices A and B are square matrices of the same size. Prove Tr(c(A + B)) = C (Tr(A) + Tr(B)).

alexira [117]

Answer with Step-by-step explanation:

We are given that two matrices A and B are square matrices of the same size.

We have to prove that

Tr(C(A+B)=C(Tr(A)+Tr(B))

Where C is constant

We know that tr A=Sum of diagonal elements of A

Therefore,

Tr(A)=Sum of diagonal elements of A

Tr(B)=Sum of diagonal elements of B

C(Tr(A))= $C\cdot$ Sum of diagonal elements of A

C(Tr(B))= $C\cdot$ Sum of diagonal elements of B

$C(A+B)=C\cdot (A+B)$

Tr(C(A+B)=Sum of diagonal elements of (C(A+B))

Suppose ,A= $\left[\begin{array}{ccc}1&0\\1&1\end{array}\right]$

B= $\left[\begin{array}{ccc}1&1\\1&1\end{array}\right]$

Tr(A)=1+1=2

Tr(B)=1+1=2

C(Tr(A)+Tr(B))=C(2+2)=4C

A+B= $\left[\begin{array}{ccc}1&0\\1&1\end{array}\right]+\left[\begin{array}{ccc}1&1\\1&1\end{array}\right]$

A+B= $\left[\begin{array}{ccc}2&1\\2&2\end{array}\right]$

C(A+B)= $\left[\begin{array}{ccc}2C&C\\2C&2C\end{array}\right]$

Tr(C(A+B))=2C+2C=4C

Hence, Tr(C(A+B)=C(Tr(A)+Tr(B))

Hence, proved.

5 0

3 years ago

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Pie

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Step-by-step explanation:

fvfnvfvfvhfbvbfdbvkurbghrsvrbagiwrgyq4tifdjbgiurwbgudfvbfsvbdhbfrifbeqyvbafwuvbrwuvbfausfbvkfdvyawrvefawevbrwugvtgbsfhvbcvfrvsafhvbarukvfshovfyuvbeuvbfoavbsfuygbreyghteufniuvehjtgidxvbtaegnveriusdfnjadnhguiwbfvkjeuigbwriokfjaicfdigseuifjgdgnsfuidvbrsguibtdgnpifuewngvhfsguipNV ijvnsidnhdfurhuaevawrbghwlabvyulzfsbvkhSDJvjsfdgntslvbdfjhgbfuyvfijgsdnvuierwnfliwdhpirqwnvdshlzcbaelfihvbglf

7 0

3 years ago

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OverLord2011 [107]

Answer:

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