<span>There are a few ways that may cause me to forget the process of classical conditioning. First, I could be having retroactive interference. In this case, the newer information that I am just now learning about could be interfering with my retrieval of previous information. Second, I could be experiencing decay. This would mean that it’s been so long since I’ve learned about classical conditioning that my memory trace has not been used and I’ve started to forget about it. Finally, I also could simply have failed to process the memory in a process known as encoding failure. (One more option is that I am suffering from retrograde amnesia, but that is unlikely).</span>
The Salaries of 8 statistics professors are as follows: $65,000, $72,000, $68,000, $63,000, $70,000, $71,000, $76,000, and $120,
PilotLPTM [1.2K]
Answer:
Median
Explanation:
It would be the median because the outlier of 120,000 does not allow a successful average result for the mean. The median considers the numbers from 60,000-76,000 more and it due to the fact that these set of numbers are prevalent in the data, they should also be prioritized, especially over an outlier.
<h2>Orbital Period:</h2>
- To answer this problem, we must employ the gravitational notion and equation. We already know that gravitational force provides the required centripetal force for orbital motion. As a result of matching gravitational and centripetal forces, we may get the equation for orbital time period.
<h2>Answer and Explanation:</h2><h3>Given:</h3>
- Mass of Sun (M) = 1.99 * 10^30 Kg
- Orbital radius of the Neptune
- (R) = 30 A.U. = 30 * (1.496 * 10^11) m
- R = 44.88 * 10^11 m
Now we know that the time period is given by
T^2 = 4π^2R^3/GM
T^2 = 4π^2*(44.88*10^11)^3/6.67*10^-11*(1.99*10^30)
T = 5.19 * 10^9 s
Now we know that
1 year = 3.154 * 10^7 s
Therefore, T = 5.19*10^9 s/ 3.154 * 10^7 (s/year)
T = 164.4 year
This would be the atomic mass. Hope this helps!! :)
