add the 2 probabilities together:
0.297 + 0.423 = 0.72
Answer is C
Ummm look it up or ask the teacher I thought I had the answer but I don’t sorry
Answer: Y= 3/2x-8=
Step-by-step explanation:Y=4 M= 3/2. X=-8
Y=mx+b
4 = 3/2(8)+b
4= 24/2+b
4= 12+b
-12=-12
-8=b
Answer and Step-by-step explanation:
C(x) be the statement "x has a cat"
D(x) be the statement "x has a dog"
F(x) be the statement "x has a ferret".
Universe = x = all students in your class.
a) A student in your class has a cat, a dog and a ferret
= ∃x(C(x) ∧ D(x) ∧ F(x))
b) All students in your class have a cat, a dog, or a ferret = ∀x(C(x) ∨ D(x) ∨ F(x))
c) Some students in your class has a cat and a ferret but not a dog = ∃x (C(x) ∧ F(x) ∧ ¬D(x))
d) No student in this class has a cat, a dog and a ferret ¬∃x (C(x) ∧ D(x) ∧ F(x))
e) For each of the three animals, cats, dogs and ferrets, there is as student in your class who has one of the three animals. (∃xC(x)) ∧ (∃xD(x)) ∧ (∃xF(x))