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Roman55 [17]
3 years ago
9

For f(x)=4x+1 and g(x)=x^-5, find (f+g)(x)

Mathematics
2 answers:
Jlenok [28]3 years ago
8 0

ANSWER

(f + g)(x) =  \frac{4{x}^{6} \:  + {x}^{5}   + 1 }{ {x}^{5} }

EXPLANATION

The given functions are:

f(x) = 4x + 1

and

g(x) =  {x}^{ - 5}

We now want to find

(f + g)(x)

We use this property of Algebraic functions.

(f + g)(x) = f(x) + g(x)

We substitute the functions to get:

(f + g)(x) = 4x + 1 +  {x}^{ - 5}

Writing as a positive index, we get:

(f + g)(x) = 4x + 1 +   \frac{1}{ {x}^{5} }

The property we used to obtain the positive index is

{a}^{ - n} = \frac{1}{ {a}^{n}}

We now collect LCD to get:

(f + g)(x) =  \frac{4x \cdot {x}^{5} \:  + {x}^{5}   + 1 }{ {x}^{5} }

This simplifies to:

(f + g)(x) =  \frac{4{x}^{6} \:  + {x}^{5}   + 1 }{ {x}^{5} }

Elanso [62]3 years ago
5 0

Answer:

x^(-5)+4x+1

given f(x)=4x+1 and g(x)=x^(-5)

Step-by-step explanation:

f(x)=4x+1

g(x)=x^(-5)

(f+g)(x) means you are just going to do f(x)+g(x)

or (4x+1)+(x^(-5))

There are absolutely no like terms so it can't be simplified. We can use commutative and associative property to rearrange the expression.

x^(-5)+4x+1

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