The distance from Humood's house to the school is 500m
<h3>How to determine the distance from Humood's house to the school?</h3>
The given parameters are:
Humood's house is (-5,7)
The school is (3,1)
The distance between both points is calculated using
Substitute the known values in the above equation
Evaluate
d = 10
Each unit in the graph is 50m.
So, we have
Distance =10 * 50m
Evaluate the product
Distance = 500m
Hence, the distance from Humood's house to the school is 500m
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You would have to find out how many square feet the lawn is first:
70 x 50 = 3500 square feet
You are told that one pound = 200 square feet so use this to calculate how many pound you’ll need for 3500 square feet.
3500 square feet divided by 200 square feet = 17.5 pounds
Answer: 17.5 pounds
Answer: O 3-7,5, 18, 24, 32}
O {-9, 7, 15, 22, 26}
these two sets are not equal
The left side was cut out but x will be on top and 5 in the lower square. The last one is the answer.
It turns out that 5% of 400 is 20.
(1/20)*400=20.
So Ian was being paid £400 a week before he was given a pay rise.
