All categories

1 year ago

Which of the following describes the graph of y=[x-2]?

Mathematics

1 answer:

kow [346]1 year ago

7 0

Answer:

What are the answer choices, if you have any?.

Step-by-step explanation:

You might be interested in

Calculate the perimeter and area for the parallelogram if a = 2.8 ,b = 16.5 and h = 11.5

Nana76 [90]

Perimeter = 2(a+b)

= 2(2.8+16.5)

=2(19.3)

Perimeter = 38.6

Area=base x height

=2.8 x 11.5

=32.2

3 0

3 years ago

Read 2 more answers

The time, t, required to drive to a certain distance varies inversely with the speed, r. if it takes 12 hours to drive the dista

kap26 [50]

T = k/R where k is the constant of variation, T=time and R=speed.
Plug in the given values:-
12 = k/60
k = 12*60 = 720
So the equation of variation is T = 720/R

At 85 mph we have

T = 720 / 85 = 8.47 hours (answer)

8 0

2 years ago

Solve –16t² +144= 0 to find the number of seconds, t, it takes for an object dropped from 144 ft above the ground to hit the gro

Vlad1618 [11]

Answer:

h(t) = -16t2 + 144

h(1) = -16(12) + 144 = 128 ft

h(2) = -16(22) + 144 = 80 ft

h(2) - h(1) = 80 - 128 = -48 ft

It fell 48 ft between t = 1 and t = 2 seconds.

It reaches the ground when h(t) = 0

0 = -16t2 + 144

t = √(144/16) s = 3s

It reaches the ground 3s after being dropped.

Step-by-step explanation:

6 0

2 years ago

Tikiro places a wrench on a nut and applies a downward force of 32 pounds to tighten the nut. If the center of the nut is at the

Butoxors [25]

Answer:

Answer: b. 20.8 ft-lb

Step-by-step explanation:

7 0

3 years ago

If tan theta =3, find the value of tan theta + tan (theta+pi) + tan (theta +2pi)

sweet-ann [11.9K]

Answer:

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9$

Step-by-step explanation:

Given

$tan\theta = 3$

Required

Find

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi)$

Calculate $tan(\theta + \pi) \ and\ tan(\theta+2\pi)$

Using tan rule

$tan(\theta + \pi) = \frac{tan\theta + tan\pi}{1 - tan\theta tan\pi}$

So:

$tan(\theta + \pi) = \frac{tan\theta + 0}{1 - tan\theta *0}$

$tan(\theta + \pi) = \frac{tan\theta}{1 }$

$tan(\theta + \pi) = \tan\theta$

$tan(\theta+2\pi)$

$tan(\theta + 2\pi) = \frac{tan\theta + tan2\pi}{1 - tan\theta tan2\pi}$

$tan(\theta + 2\pi) = \frac{tan\theta + 0}{1 - tan\theta *0}$

$tan(\theta + 2\pi) = \tan\theta$ '

'So:

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi)$ $= tan\theta +tan\theta +tan\theta$

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 3+3+3$

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9$

4 0

2 years ago