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irina1246 [14]
3 years ago
15

Hello! I need some help figuring out the following parts of trigonometry. Since this is a rather difficult math term to understa

nd, I gave out 50 points. :D
Bubble in the correct answer choices that go with the correct sentences.


The ratio of the side opposite from an acute angle and the hypotenuse. Opposite/Hypotenuse

A) Trigonometric Ratio
B) Tangent
C) Sine
D) Degree
E) Cosine


The ratio of the side adjacent an acute angle and the hypotenuse. Adjacent/Hypotenuse


A) Trigonometric Ratio
B) Tangent
C) Sine
D) Degree
E) Cosine


The ratio of the side opposite from an acute angle and the side adjacent to an acute angle. Opposite/Adjacent


A) Trigonometric Ratio
B) Tangent
C) Sine
D) Degree
E) Cosine

Explain your answers clearly, please. Will pick Brainliest Answer!
Thank you!
Mathematics
2 answers:
Zina [86]3 years ago
4 0
Alright so these ratios have many different forms but the way I use to remember the trigonometric ratios is:
SOH
CAH
TOA

This means:
Sine --> Opposite/Hypotenuse
Cosine --> Adjacent/Hypotenuse
Tangent --> Oppositie/Adjacent

With that in mind, number 1:
Would be Sine, or C.

Number 2 would be, Cosine, or E.

And number 3 would be Tangent, or B.

Hope that was helpful. 
lara [203]3 years ago
4 0
Solutions 

Trigonometry is the measuring of angles and sides of triangles. In a triangle, there are six elements: 3 sides and 3 angles. A triangle had an <span><span>Adjacent which is an adjacent next to the angle θ. An </span><span>Opposite is the opposite the angle θ and </span><span>the longest side which is the <span>Hypotenuse.
</span></span></span>
Sine Function: sin(θ<span>) = Opposite / Hypotenuse

</span>Cosine Function: cos(θ<span>) = Adjacent / Hypotenuse
</span>
Tangent Function: tan(θ) = Opposite / Adjacent

Answers

Number 1 = (C) 

Number 2 = (E)

<span> Number 3 = (B)</span>


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Julia rides her horse 18 km with a constant speed of 6km/hr and another 24 km with a constant speed of 12 km/hr. What is her ave
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Answer:

8.4 km/hr.

Step-by-step explanation:

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\text{Time}=\frac{\text{Distance}}{\text{Speed}}

\text{Time taken to cover 18 km}=\frac{18\text{ km}}{\frac{6\text{km}}{\text{hour}}}

\text{Time taken to cover 18 km}=\frac{18\text{ km}}{6}\times\frac{\text{hour}}{\text{km}}

\text{Time taken to cover 18 km}=\frac{18}{6}\times\text{hour}

\text{Time taken to cover 18 km}=3\text{ hour}

We are also told that she rides another 24 km with a constant speed of 12 km/hr.

Let us find the time taken by Julia to cover a distance of 24 km.

\text{Time taken to cover 24 km}=\frac{24\text{ km}}{\frac{12\text{km}}{\text{hour}}}

\text{Time taken to cover 24 km}=\frac{24\text{ km}}{12}\times\frac{\text{hour}}{\text{km}}

\text{Time taken to cover 24 km}=\frac{24}{12}\times\text{hour}

\text{Time taken to cover 24 km}=2\text{ hour}

Since we know that \text{Average speed}=\frac{\text{Total distance}}{\text{Total time}}.

Upon substituting our values in above formula we will get,

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5 0
4 years ago
PLEASE HELP!!! <br> WHICH OF THE FOLLOWING FUNCTIONS IS GRAPHED BELOW?
SashulF [63]

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7 0
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BigorU [14]
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