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Anika [276]
2 years ago
13

Why is it difficult to hame lonic Compounds that Contain transition metals ?

Chemistry
1 answer:
belka [17]2 years ago
5 0
Answer:
transition metals have more than 1 oxidation numbers
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4 years ago
HI PLEASE HELP ASAP MULTIPLE CHOICE question. I just want to know which will favour the products the most and the least. THANK Y
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Answer:

  1. answer c is the answer

Explanation:

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3 years ago
How is a scientific experiment different from other investigations
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To start one difference between the two is that a scientific experiment is meant to be repeated and to be formed into a theory and/or a scientific law. Scientific experiments also use different types of data, for instance, you could be recording how much a plant grows in a month, in an experiment you would focus on the types of soil being used. In an investigation you would observe how tall the plant actually grew.
8 0
4 years ago
You have 500.0 ml of a buffer solution containing 0.30 m acetic acid (ch3cooh) and 0.20 m sodium acetate (ch3coona). what will t
Nataly [62]
First, we should get moles acetic acid = molarity * volume

                                                                =0.3 M * 0.5 L

                                                                =  0.15 mol

then, we should get moles acetate = molarity * volume

                                                           = 0.2 M * 0.5L

                                                           = 0.1 mol

then, we have to get moles of OH- which added:

moles OH- = molarity  * volume

                   = 1 M    * 0.02L

                  = 0.02 mol

when the reaction equation is:


                 CH3COOH  +  OH-  → CH3COO-   +  H2O


moles acetic acid after adding OH- = (0.15-0.02) 
                                             
                                                            =  0.13M                                       

moles acetate after adding OH- =  (0.1 + 0.02)

                                                      =   0.12 M

Total volume = 0.5 L + 0.02 L= 0.52 L

∴[acetic acid] = moles acetic acid after adding OH- / total volume

                        = 0.13mol / 0.52L

                       = 0.25 M

and [acetate ) = 0.12 mol / 0.52L
 
                        = 0.23 M

by using H-H equation we can get PH:

PH = Pka + ㏒[salt/acid]

when we have Ka = 1.8 x 10^-5

∴Pka = -㏒Ka 

        = -㏒ 1.8 x 10^-5

       = 4.7

So by substitution:

∴ PH = 4.7 + ㏒[acetate/acetic acid]

         = 4.7 + ㏒(0.23/0.25)

        = 4.66
6 0
3 years ago
0. 01 M HCl solution has a pH of 2. Suppose that during the experiment, both the universal pH indicator and the cabbage indicato
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Answer:

a.) It matches the universal pH indicator and is indicating the proper pH.

Explanation:

it says its the answer.

5 0
2 years ago
Read 2 more answers
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