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2 years ago

14

A 3.0-mol sample of kclo3 was decomposed according to the equation 2kclo3(s) --> 2kcl(s) + 3o2(g) how many moles of o2 are fo

rmed assuming 100% yield? *

1 answer:

d1i1m1o1n [39]2 years ago

5 0

2moles of O2 are formed.

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Is usually categorized to a specific area in the state known as a soil series

Vikentia [17]

Answer:

Soil series as established by the National Cooperative Soil Survey of the United States Department of Agriculture (USDA) Natural Resources Conservation Service are a level of classification in the USDA Soil Taxonomy classification system hierarchy. The actual object of classification is the so-called soil individual, or pedon.[1] Soil series consist of pedons that are grouped together because of their similar pedogenesis, soil chemistry, and physical properties. More specifically, each series consists of pedons having soil horizons that are similar in soil color, soil texture, soil structure, soil pH, consistence, mineral and chemical composition, and arrangement in the soil profile.[2] These result in soils which perform similarly for land use purposes.

Explanation:

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3 years ago

Find the pH of the equivalence point and the volume (mL) of 0.0372 M NaOH needed to reach the equivalence point in the titration

elixir [45]

Answer:

8.54

Explanation:

At equivalence point :

42.2 X 0.052 = Vol. NaOH X 0.0372

Vol of NaOH = 2.1944/0.0372 = 58.99 ml

So volume of NaOH recquired to reach equivalence point = 58.99 ml

Number of miliimoles of CH3COOH = molarity X volume in ml = 42.2 X 0.052 = 2.1944 millimoles

Number of millimoles of NaOH = 58.99 X 0.0372 = 2.1944

Now CH₃COOH and NaOH reacts to give CH₃COONa according to the reaction :

CH₃COOH + NaOH ------> CH₃COONa + H₂O

1 mole of CH₃COOH reacts with 1 mole of NaOH to give 1 mole of CH₃COONa

So 2.1944 millimoles of CH₃COOH will react with 2.1944 millimoles of NaOH to give 2.1944 millimoles of CH₃COONa

So all the acid (CH₃COOH) and base (NaOH) has been converted into salt (CH₃COONa) so there is no acid or base left.

Now molarity of CH₃COONa = number of millimoles of CH₃COONa/total volume in ml = 2.1944/(58.99 + 42.2) = 2.1944/101.19 = 0.02169 M

So using the hydrolysis equation :

pH = 1/2 [ pKw + pKa + log c ]

Ka for acetic acid = 1.75 X 10⁻⁵

so pKa = -log (1.75 X 10⁻⁵) = 4.74

Kw = 10⁻¹⁴

so pKw = -log 10⁻¹⁴ = 14

c = 0.02169

so log c = log 0.02169 = -1.66

putting the values....

pH = 1/2 [14 + 4.74 - 1.66 ]

pH = 1/2 [ 17.08] = 8.54

6 0

3 years ago

Read 2 more answers

[HELP PLEASE]What is the electronegativity from largest to smallest for Chlorine [Cl], Carbon [C], and Arsenic [As]? (hint: use

valentina_108 [34]

Answer:

Electronegativity varies in a predictable way across the periodic table. Electronegativity increases from bottom to top in groups, and increases from left to right across periods. Thus, fluorine is the most electronegative element, while francium is one of the least electronegative.Explanation:

8 0

3 years ago

Which statement regarding this equation is TRUE?

noname [10]

Answer:

iron (III) oxide is a gas

8 0

2 years ago

Calculate the molarity of each of the following

Alenkasestr [34]

Answer:

a. 1.21M

b. 0.119M

c. 0.00496M

Explanation:

Molarity, M, is an unit of concentration defined as the ratio between moles of solute and liters of solution:

a. 4.35 mol LiCl / 3.60L = 1.21M

b. 29.43gC6H12O6 * (1mol / 180.16g) = 0.1634moles / 1.37L = 0.119M

<em>Molar mass C6H12O6: 180.16g/mol</em>

c. 34.5mg NaCl = 0.0345g * (1mol / 58.44g) = 5.9x10⁻⁴moles / 0.1191L = 0.00496M

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2 years ago