Convert 5.43 x 10-6 Mm to cm

What would the formula of an ionic compound made of Aluminum and Oxygen be?

yan [13]

Answer:

Sodium Aluminate

Formula:-

$\quad{:}\longrightarrow\sf NaAlO_2$

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Melting points and boiling points of some ionic compounds

$\boxed{\begin{array}{|c|c|c|c|} \cline {1-4}\Large\sf {Ionic\:Compounds} & \sf \Large {Chemical\:Formula} & \Large \sf{Melting\:point_{(k)}} & \Large\sf {Boiling\:point_{(k)}} \\ &&& \\ \cline {1-4} \sf Sodium\:Chloride & \sf NaCl & 1074 & 1686 \\ &&& \\ \cline {1-4} \sf Lithium\:Chloride & \sf \sf LiCl & 887 & 1600 \\ &&& \\ \cline {1-4} \sf Calcium\:Chloride & \sf CaCl_2 & 1045 & 1900 \\ &&& \\ \cline {1-4} \sf Calcium\:Oxide & \sf CaO & 2850 & 3120 \\ &&& \\ \cline {1-4} \sf Magnesium\:Chloride & \sf MgCl_2 & 981 & 1685 \\ &&& \\ \cline {1-4} \end{array}}$

8 0

2 years ago

Which of the following represent a mixture?

7nadin3 [17]

The answer is B NaCI solid

6 0

3 years ago

which change in the temperature of the one gram sample of water would cause the greatest increase in average kinetic energy of i

LenaWriter [7]

Maybe about in the 50ths

8 0

3 years ago

How many milliliters of 0.200 m fecl3 are needed to react with an excess of na2s to produce 1.38 g of fe2s3 if the percent yield

ahrayia [7]

Answer: 100 ml


Explanation:

1) Convert 1.38 g of Fe₂S₃ into number of moles, n

i) Formula: n = mass in grass / molar mass

ii) molar mass of Fe₂S₃ =2 x 55.8 g/mol + 3 x 32.1 g/mol = 207.9 g/mol


iii) n = 1.38 g / 207.9 g/mol = 0.00664 moles of Fe₂S₃


2) Use the percent yield to calculate the theoretical amount:


65% = 0.65 = actual yield/ theoretical yield =>

theoretical yield = actual yield / 0.65 = 0.00664 moles / 0.65 = 0.010 mol Fe₂S₃

3) Chemical equation:


 3 Na₂S(aq) + 2 FeCl₃(aq) → Fe₂S₃(s) + 6 NaCl(aq)

4) Stoichiometrical mole ratios:


3 mol Na₂S : 2 mol FeCl₃ : 1 mol Fe₂S₃ : 6 mol NaCl

5) Proportionality:

2moles FeCl₃ / 1 mol Fe₂S₃ = x / 0.010 mol Fe₂S₃

=> x = 0.020 mol FeCl₃

6) convert 0.020 mol to volume


i) Molarity formula: M = n / V


ii) V = n / M = 0.020 mol / 0.2 M = 0.1 liter = 100 ml

3 0

3 years ago

Read 2 more answers

2KCIO3 -2KCL + 302

Firlakuza [10]

Answer:

a. 6 moles of O₂

b. 4.06×10²⁴ molecules of O₂

c. 3.04 g of KCl

Explanation:

Reaction of decomposition is:

2KClO₃ → 2KCl + 3O₂

a. See stoichiometry value

2 moles of potassium chlorate can decompose to 2 moles of potassium chloride and 3 moles of oxygen. Ratio is 2:3

If 2 moles of KClO₃ can decompose to 3 moles of O₂

Then 4 moles, may decompose to (4 . 3)/2 = 6 moles of O₂

b. In this case, the stoichiometry is the same.

Per 2 moles of KClO₃, I produce 2 moles of KCl

Then, 4.5 moles of KCl, were produced by 4.5 moles of KClO₃

We apply, the last relation:

(4.5 . 3) /2 = 6.75 moles of O₂ are also produced.

How many molecules are in 6.75 moles?

6.75 mol . 6.02×10²³ molecules/mol = 4.06×10²⁴ molecules of O₂

c. First of all, we convert the mass to moles:

5g . 1mol /122.55g = 0.0408 moles of salt

As ratio is 2:2, 0.0408 moles of salt, decompose to 0.0408 moles of KCl

We convert the moles to mass: 0.0408 mol . 74.55g /mol = 3.04g

5 0

2 years ago