PLZZZ HELP. Just say yellow goes under ..... for example.

The motion of a toy truck was investigated. The total distance covered vs. time was recorded in the table.

DIA [1.3K]

Answer:

Where the chart pls I can answer

Explanation:

3 0

2 years ago

The density of a pure substance is its mass per unit volume. The density of cresol has been measured to be 1024 g/L . Calculate

Ierofanga [76]

Answer: The mass of 405 ml of cresol is 415 grams

Explanation:

Density is defined as the mass contained per unit volume.

$Density=\frac{mass}{volume}$

Given : Density of cresol = 1024 g/L

Volume of cresol = 405 ml = 0.405 L ( 1L=1000ml)

Putting in the values we get:

$1024g/L=\frac{mass}{0.405L}$

$mass=1024g/L\times 0.405L=415g$

Thus mass of 405 ml of cresol is 415 grams

3 0

2 years ago

How do the bones protect your organs?

Sever21 [200]

Answer:

Yes

Explanation:

Bones sustain our bodies, and help shape our form. While very thin, the bones are large enough to bear all of our mass. Bones shield the organs of the body too. The skull supports the brain, and creates the face shape.

8 0

2 years ago

What is the molarity of a NaOH solution when 22.14 mL of 0.105 M oxalic acid is needed to

jeka57 [31]

The molarity of the NaOH solution required for the reaction is 0.186 M

We'll begin by writing the balanced equation for the reaction

H₂C₂O₄ +2NaOH —> Na₂C₂O₄ + 2H₂O

From the balanced equation above,

The mole ratio of the acid, H₂C₂O₄ (nA) = 1

The mole ratio of the base, NaOH (nB) = 2

From the question given above, the following data were obtained:

Volume of the acid, H₂C₂O₄ (Va) = 22.14 mL

Molarity of the acid, H₂C₂O₄ (Ma) = 0.105 M

Volume of the base, NaOH (Vb) = 25 mL

<h3>Molarity of the base, NaOH (Mb) =? </h3>

MaVa / MbVb = nA/nB

(0.105 × 22.14) / (Mb × 25) = 1/2

2.3247 / (Mb × 25) = 1/2

Cross multiply

Mb × 25 = 2.3247 × 2

Mb × 25 = 4.6494

Divide both side by 25

Mb = 4.6494 / 25

Therefore, the molarity of the base, NaOH solution is 0.186 M

Learn more: brainly.com/question/25739717

4 0

2 years ago

1. Methane (CH4) combusts as shown in the equation below. If 3 moles of methane were used in the combustion, what would be the c

umka2103 [35]

Answer:

The change in enthalpy in the combustion of 3 moles of methane = -2406 kJ

Explanation:

<u>Step 1: </u>The balanced equation

CH4(g) + 2 O2(g) → CO2(g) + 2 H2O(g) ΔH = -802 kJ

<u>Step 2:</u> Given data

We notice that for 1 mole of methane (CH4), we need 2 moles of O2 to produce : 1 mole of CO2 and 2 moles of H20.

The enthalpy change of combustion, given here as Δ H , tells us how much heat is either absorbed or released by the combustion of <u>one mole</u> of a substance.

In this case: we notice that the combustion of 1 mole of methane gives off (because of the negative number), 802.3 kJ of heat.

<u>Step 3: </u>calculate the enthalpy change for 3 moles

The -802 kj is the enthalpy change for 1 mole

The change in enthalpy for 3 moles = 3* -802 kJ = -2406 kJ

The change in enthalpy in the combustion of 3 moles of methane = -2406 kJ

5 0

3 years ago