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Anettt [7]
2 years ago
11

SOMEBODY HELP ME PLS!

Mathematics
1 answer:
babunello [35]2 years ago
3 0

Answer:

To find the value of y from a given value of x, find the position of x on the x-axis, then trace vertically until you meet the line.  Once you meet the line, trace horizontally to the y-axis to find the corresponding value of y.

To find the value of x from a given value of y, find the position of y on the y-axis, then trace horizontally until you meet the line.  Once you meet the line, trace vertically to the x-axis to find the corresponding value of x.

From inspection of the graph,

when x = 1,  y = -1

when x = 0, y = 2

when x = 2, y = -4

Therefore,

\begin{array}{| c | c |}\cline{1-2} x & y\\\cline{1-2} 1 & -1 \\\cline{1-2} 0 & 2 \\\cline{1-2} 2 & -4 \\\cline{1-2}\end{array}

To find the equation of the line, find the slope:

\sf slope\:(m)=\dfrac{change\:in\:y}{change\:in\:x}=\dfrac{2-(-1)}{0-1}=-3

Then use one of the points and the found slope with the point-slope form of a linear equation: y-y_1=m(x-x_1)

\implies y-2=-3(x-0)

\implies y=-3x+2

So the equation of this line is: y=-3x+2

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Answer:

( 1, -3 )

Step-by-step explanation:

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slamgirl [31]

Answer:D

Step-by-step explanation:

First, converting R percent to r a decimal

r = R/100 = 8.5%/100 = 0.085 per year

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DENIUS [597]
Hello,

Reminders:
$\sum_{i=1}^{n} i= \dfrac{n(n+1)}{2}$



$ \sum_{i=1}^{n} i^2= \dfrac{n(n+1)}{2}$


$ \sum_{i=1}^{n} i^3= \dfrac{n^2(n+1)^2}{4} $


n=6\\
x_{0}=0\\
x_{n}=3\\
\Delta= \dfrac{x_n-x_0}{n}=0.5\\


x_{i} =0+\Delta*i= \frac{i}{2}

$ \sum_{i=1}^{n}\ \Delta*f(x_{i})=\sum_{i=1}^{6}\  \dfrac{i^3/8-6i}{2} $
$= \dfrac{1}{2}\sum_{i=1}^{6}  (\frac{i^3}{8} -6i)=\dfrac{1}{16}*\frac{(6*7)^2}{4}- \frac{9*7}{2}= -3.9575


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<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark"> xls </span>
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