Answer:
To find the value of y from a given value of x, find the position of x on the x-axis, then trace vertically until you meet the line. Once you meet the line, trace horizontally to the y-axis to find the corresponding value of y.
To find the value of x from a given value of y, find the position of y on the y-axis, then trace horizontally until you meet the line. Once you meet the line, trace vertically to the x-axis to find the corresponding value of x.
From inspection of the graph,
when x = 1, y = -1
when x = 0, y = 2
when x = 2, y = -4
Therefore,

To find the equation of the line, find the slope:

Then use one of the points and the found slope with the point-slope form of a linear equation: 


So the equation of this line is: 