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julsineya [31]
2 years ago
7

Build the graph of the equation (x-2)(y-3)=0

Mathematics
1 answer:
andre [41]2 years ago
4 0

Answer:I don’t know the answer but something that always helps me is soupCalculator it will give you the answer and show you step by step

Step-by-step explanation:

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Answer:

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3 0
3 years ago
Given that cos θ = –12∕13 and θ is in quadrant III, find csc θ.
Trava [24]

Answer:

A

Step-by-step explanation:

We are given:

\displaystyle \cos(\theta)=-\frac{12}{13},\,\theta\in\text{QIII}

Since cosine is the ratio of the adjacent side over the hypotenuse, this means that the opposite side is (we can ignore negatives for now):

o=\sqrt{13^2-12^2}=\sqrt{25}=5

So, the opposite side is 5, the adjacent side is 12, and the hypotenuse is 13.

And since θ is in QIII, sine/cosecant is negative, cosine/secant is negative, and tangent/cotangent is positive.

Cosecant is given by the hypotenuse over the opposite side. Thus:

\displaystyle \csc(\theta)=\frac{13}{5}

Since θ is in QIII, cosecant must be negative:

\displaystyle \csc(\theta)=-\frac{13}{5}

Our answer is A.

7 0
2 years ago
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stepan [7]

Answer:24v+24w-16

Step-by-step explanation:

8(3v+3w-2)

8 times 3 =24

So 24v+24w

Then 8 times 2=16

So the answer would be 24v+24w-16

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3 years ago
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8x + 4y = 20

4y = 20 - 8x

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