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sladkih [1.3K]
2 years ago
5

Suppose the base and height ( 8 and 6) are multiplied by 1/2, what effect would this have on the area

Mathematics
1 answer:
Feliz [49]2 years ago
6 0

Answer:

Here is the answer hope it helps:)

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Answer:

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Calculate the sample standard deviation of data from Question 1<br> 76,45,64,80,92
mash [69]

Answer:

S.D = 15.98

Step-by-step explanation:

Given: 76,45,64,80,92

Required: Determine the standard deviation

We start by calculating the mean

Mean = \frac {\sum x}{n}

Where x-> 76,45,64,80,92 and n = 5

Mean = \frac {76+45+64+80+92}{5}

Mean = \frac{357}{5}

Mean = 71.4

Subtract Mean (71.4) from each of the given data

76 - 71.4 = 4.6\\45 - 71.4 = -26.5\\64 - 71.4 = -7.4\\80 - 71.4 = 8.6\\92 - 71.4 = 20.6

Determine the absolute value of the above result

|4.6| = 4.6\\|-26.5| = 26.5\\|-7.4| = 7.4\\|8.6| = 8.6\\|20.6| = 20.6

Square Individual Result

4.6^2 = 21.16 \\26.5^2 = 702.25\\7.4^2 = 54.76\\8.6^2 = 73.96\\20.6^2 = 424.36

Calculate the mean of the above result to give the variance

Mean = \frac {\sum x}{n}

Mean = \frac{21.16 + 702.25 + 54.76 + 73.96 + 424.36}{5}\\Mean = \frac{1276.49}{5}\\Mean = 255.298

Hence, Variance = 255.298

Standard Deviation is calculated by \sqrt{Var}

SD = \sqrt{255.298}

S.D = 15.9780474402

S.D = 15.98 (Approximated)

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A race is 1 2/3 miles long. If you just run half of the race, how long far have you run?
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You would run 2.5/3 miles or .833 miles
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✓-32<br><br>imaginary numbers​
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Answer:

<em><u>√</u></em><em><u>-32 imaginary numbers</u></em>

\sqrt{ - 32} \\   =  \sqrt{ - 1 \times 16 \times 2}  \\  =  \sqrt{ - 1}  \times  \sqrt{16}  \times  \sqrt{2}  \\  =\boxed{ 4 \sqrt{2} i}

<h3>4√2i is the right answer.</h3>
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What is 5.3 as a mixed number
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5 3/10 because if it is in the tenth place it will be over 10 then 5 is the whole numbers. Did this help?
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