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lora16 [44]
2 years ago
11

savannah works as a sales rep and receives $23.80 for every $140 she sells. what is her rate of commission?

Mathematics
2 answers:
ANTONII [103]2 years ago
8 0

Answer:

23.80/140 = 0.17 = 17%

Step-by-step explanation:

neonofarm [45]2 years ago
7 0

Answer:

23.80/140 = 0.17 = 17%

Step-by-step explanation:

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1 when -2<x<2

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Step-by-step explanation:

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The diameter of Saturn at its equator is about 120,540,000 meters. What is 120,540,000 written in word form?
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Step-by-step explanation:

Onehundred twenty-million-fivehundred forty thousand

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Read 2 more answers
A $48 game has a 9.6 percent sales tax. what is the final price jncluding tax?​
loris [4]

Answer:

52.61

Step-by-step explanation:

First let turn 9.6% into a decimal

0.096

Then,

48 x 0.096 = 4.608 {Round} 4.61

48 + 4.61=52.61

5 0
2 years ago
In a clinical trial of 268 subjects treated with a​ drug, 11​% of the subjects reported dizziness. The margin of error is plus o
Mariulka [41]

Answer:

\hat p =0.11 represent the proportion estimated of subjects reported with dizziness

n = 268 represent the random sample selected

\hat q = 1-\hat p = 1-0.11= 0.89 represent the proportion of subjects No reported with dizziness

E= 0.04 = 4% represent the margin of error for the confidence interval

\alpha= 1-0.90 =0.1 and this value represent the significance level of the test or the probability of error type I

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Solution to the problem

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

The margin of error is given by:

ME= z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

Lower= 0.11-0.04 = 0.07

Upper= 0.11+0.04 = 0.15

And for this case we have the following info:

\hat p =0.11 represent the proportion estimated of subjects reported with dizziness

n = 268 represent the random sample selected

\hat q = 1-\hat p = 1-0.11= 0.89 represent the proportion of subjects No reported with dizziness

E= 0.04 = 4% represent the margin of error for the confidence interval

\alpha= 1-0.90 =0.1 and this value represent the significance level of the test or the probability of error type I

4 0
3 years ago
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