Question

There are 300 seconds between the bell to the end of first and the bell to begin second period. A student exits his first period class immediately after the bell to end first period and enters the doorway of the second period class at the moment the bell to begin second period rings. He travels the route contained in the chart provided. What is the students average velocity?

Answer 1

The average velocity is a vector magnitude we can find that its value is:

           v = 3.63 10-2 m/ s

with a direction 74 to the South of the East

Giving parameters

• The tabulated displacements

• The time of the motion t = 300 s

To find

• Average speed

The velocity in a vector quantity that is defined as the change in displacement between time during the interval

               v = $\frac{\Delta s}{\Delta t}$

Where v is the veloicity, Δs and Δt are de positivo and time variation

To find the displacement let's use the Pythagoras'  theorem

           d = $\sqrt{(\Delta x)^2 + (\Delta y)^2}$

We assume that the displacements to the right (east) and upwards (north) are positive

          Δx = 17-14

          Δx = 3 m

          Δy = 12 -22.5

          Δy = -10.5 m

The distance traveled is

          d = $\sqrt{3^2 + 10.5^2 }$

          d = 10.9 m

The speed module is

          v = 10.9 / 300

           v = 3.63 10⁻² m / s

The direction of this velocity is given by the angle of this displacement can be found using trigonometry

           tan θ = $\frac{\Delta y}{\Delta x}$

           θ = tan⁻¹ $\frac{\Delta y}{\Delta x}$

           θ = tan⁻¹ $\frac{-10.5}{3}$

           θ = -74º

This angle is measured clockwise from the positive side of the x-axis.

Orea way to give this angle is

             θ = 74 south of East

In conclusion the average speed is

           v = 3.63 10-2 m / s

With a direction 74 to the South of the East

Learn more about average velocity here:

brainly.com/question/12322912