Answer:
175.5 kN
Explanation:
We find the acceleration of the Airbus A320 jetliner from,
a = (v - u)/t where u = initial velocity of jetliner = 0 m/s (since it starts from rest), v = final velocity of jetliner = 82 m/s and t = time for velocity change = 35 s
So a = (v - u)/t = (82 m/s - 0 m/s)/35 s = 82 m/s ÷ 35 s = 2.34 m/s²
Now, the thrust of the engines on the jetliner T = ma where m = mass of jetliner = 75,000 kg and a = acceleration of jetliner = 2.34 m/s²
T = ma
= 75,000 kg × 2.34 m/s²
= 175500 N
= 175.5 kN
Answer:
I'm not really sure but I think it's choice a
We have that the speed over the ground of a mosquito flying 2 m/s relative to the air against a 2 m/s headwind is
X=0m/s
From the question we are told that
mosquito flying 2 m/s
against a 2 m/s headwind
Generally
The speed over the ground is the Flight Speed minus resistance speed
Generally the equation for the speed over the ground is mathematically given as
X=Flight Speed-resistance speed
Therefore
X=2-2
X=0m/s
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Hey! I know you've probably already finished the quiz already, but I just wanted to let you know the correct answer should be D. I wish I could tell you why, but I ended up getting that answer through a bit of trial and error myself... Anyway, good luck!
It will tend to follow a trajectory path. When a projectile is being flung or flown away by a certain type of force, the trajectory is what it follows through the means of both force and function of time itself. It's also called as flight path.
