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ziro4ka [17]
3 years ago
8

What is the average power output of an athlete who can life 9.0 * 10^2 kg 2.5 m in 2.0 s?

Physics
1 answer:
eduard3 years ago
3 0

Answer:

Average power output of athlete = 11025 Watts

Explanation:

Work done is defined as the product of force applied and the displacement perpendicular to the force.

Work = Force\times Displacement

Power is defined as work done per unit time.

Power = \frac{Work done}{Time}

Here the person lifts 900 kg.

Height = 2.5 m

Time interval = 2 seconds

Force = weight \times gravity

          = 900 \times 9.8

          = 8820 N

Work done = Force\times Displacement

                   = 8820 \times 2.5

                   = 22050 J

Power = \frac {22050}{2}

           = 11025 Watt

                 

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Flura [38]

Answer:

3.6 s

Explanation:

100 km/hr =27.77 m/s

100/27.77=3.6 sec

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2 years ago
For a demonstration, a professor uses a razor blade to cut a thin slit in a piece of aluminum foil. When she shines a laser poin
hoa [83]

Answer:

Slit width is 0.109 mm

Solution:

As per the question:

Wavelength of the light, \lambda = 680\ nm = 680\times 10^{- 9}\ m

Distance from the screen, D = 5.6 m

Bright band in the center, 2x = 8.1 cm

x = 4.05 cm

Now,

To calculate the slit width, w:

From the diffraction:

sin\theta = \frac{\lambda}{w}

For small angle:

sin\theta ≈ tan\theta = \frac{x}{D}

Also

\frac{x}{D} = \frac{\lambda }{w}

Thus

w = \frac{D}{x}\times \lambda

Substituting appropriate values in the above eqn:

w = \frac{6.5}{4.05\times 10^{-2}}\times 680\times 10^{- 9}

w = 0.109 mm

7 0
4 years ago
Which healthy snack can provide protein after physical activity?
Maksim231197 [3]
The awnser is C. yogurt
7 0
4 years ago
Read 2 more answers
The 30-kg disk is originally spinning at v = 125 rad>s. If it is placed on the ground, for which the coefficient of kinetic f
irga5000 [103]

Answer:

t = 3.82 s

Ax = 147 N  (←)

Ay = 294 N   (+↑)

Explanation:

Given

m = 30.0 Kg

ωinitial = 125 rad/s

ωfinal = 0 rad/s

μC = 0.5

R = 0.3 m

t = ?

Ax = ?

Ay = ?

For the disk, we can apply

∑ τ = I*α

where I = m*R²/2

then

⇒ R*Ffriction = (m*R²/2)*α

⇒ R*(-μC*N) = R*(-μC*m*g) = (m*R²/2)*α

⇒ α = -2*μC*g / R

⇒ α = -2*(0.5)*(9.8) / 0.3 = -32.666 rad/s²

we can use the equation to get t:

α = Δω / t      ⇒   t = Δω / α = (0 - 125) / (-32.666)

⇒   t = 3.82 s

The horizontal and vertical components of force which the member AB exerts on the pin at A during this time are

∑ Fx = 0  (+→)

Ax - Ffriction = 0

⇒  Ax = Ffriction = μC*m*g = (0.5)*(30)*(9.8) = 147 N

⇒   Ax = 147 N  (←)

∑ Fy = 0   (+↑)

⇒  Ay - m*g = 0

⇒  Ay = m*g

⇒  Ay = 30*9.8 = 294 N

⇒  Ay = 294 N   (+↑)

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3 years ago
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Answer:

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Explanation:

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