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3 years ago

What is the average power output of an athlete who can life 9.0 * 10^2 kg 2.5 m in 2.0 s?

Physics

1 answer:

eduard3 years ago

3 0

Answer:

Average power output of athlete = 11025 Watts

Explanation:

Work done is defined as the product of force applied and the displacement perpendicular to the force.

Work = $Force\times Displacement$

Power is defined as work done per unit time.

Power = $\frac{Work done}{Time}$

Here the person lifts 900 kg.

Height = 2.5 m

Time interval = 2 seconds

Force = $weight \times gravity$

= $900 \times 9.8$

= 8820 N

Work done = $Force\times Displacement$

= $8820 \times 2.5$

= 22050 J

Power = $\frac {22050}{2}$

= 11025 Watt

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A 25 Kg rock is sitting on a cliff that is 50 meters above the ground. If it fell off of the cliff, and all energy was conserved

svetlana [45]

Answer:

v = 31.32 [m/s]

Explanation:

To solve this problem we must use the principle of energy conservation, which tells us that potential energy is converted into kinetic energy or vice versa. The potential energy can be calculated by the product of mass by gravity by height.

$E_{pot}=m*g*h$

where:

Epot = potential energy [J]

m = mass = 25 [kg]

g = gravity acceleration = 9.81 [m/s²]

h = elevation = 50 [m]

Now replacing:

$E_{pot}=25*9.81*50\\E_{pot}= 12262.5[J]$

When the rock falls the potential energy is converted into kinetic energy.

$E_{pot}=E_{k}\\E_{k}=\frac{1}{2}*m*v^{2}$

where:

Ek = kinetic energy [J]

v = velocity [m/s]

Now clearing v:

$v^{2} =\frac{E_{k}*2}{m}\\v=\sqrt{(2*12262)/25}\\v = 31.32 [m/s]$

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3 years ago

Galileo’s pendulum theory stated that the time taken to swing through one complete cycle of a pendulum depends on what?

Wittaler [7]

It depends on the length of the pendulum and the strength of gravitational pull acting upon the pendulum.

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4 years ago

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The barrel of a rifle has a length of 0.855 m. A bullet leaves the muzzle of a rifle with a speed of 553 m/s. What is the accele

Novay_Z [31]

Answer:

Acceleration of the bullet will be 1778835.6 $m/sec^2$

Explanation:

We have given length of the barrel refile s= 0.855 m

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So final velocity v = 553 m/sec

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