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ziro4ka [17]
3 years ago
8

What is the average power output of an athlete who can life 9.0 * 10^2 kg 2.5 m in 2.0 s?

Physics
1 answer:
eduard3 years ago
3 0

Answer:

Average power output of athlete = 11025 Watts

Explanation:

Work done is defined as the product of force applied and the displacement perpendicular to the force.

Work = Force\times Displacement

Power is defined as work done per unit time.

Power = \frac{Work done}{Time}

Here the person lifts 900 kg.

Height = 2.5 m

Time interval = 2 seconds

Force = weight \times gravity

          = 900 \times 9.8

          = 8820 N

Work done = Force\times Displacement

                   = 8820 \times 2.5

                   = 22050 J

Power = \frac {22050}{2}

           = 11025 Watt

                 

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MA_775_DIABLO [31]

Answer:

The resistance is 3.5\times10^{-4}\ \Omega

Explanation:

Given that,

Diameter of tube = 8.5 mm

Length = 8 cm

Resistivity = 2.5 m

We need to calculate the resistance

The resistance is equal to the product of the resistivity and length divided by the area of cross section .

In mathematical form,

R = \dfrac{\rho\times l}{A}

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Put the value into the formula

R = \dfrac{2.5\times8\times10^{-2}}{3.14\times(\dfrac{8.5}{2}\times10^{-3})^2}

R=3526.32\ \Omega

R=3.5\times10^{-4}\ \Omega

Hence, The resistance is 3.5\times10^{-4}\ \Omega

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