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EastWind [94]
3 years ago
13

A principal is ordering pizzas for a school pizza party. He knows that 9 pizzas will

Mathematics
1 answer:
My name is Ann [436]3 years ago
7 0

Answer:

108 pizzas

Step-by-step explanation:

300/25 = 12 groups of 25 students

9 pizzas per group

9(12) = 108 pizzas

hope this helps

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(x+3)(3x² - 5x - 10) multiply polynomial
brilliants [131]

Answer:

  • \boxed{\sf{3x^3+4x^2-25x-30}}

Step-by-step explanation:

\underline{\text{SOLUTION:}}

To isolate the term of x from one side of the equation, you must multiply by a polynomial.

\underline{\text{GIVEN:}}

:\Longrightarrow: \sf{(x+3)(3x^2 - 5x - 10)}

<u>You have to solve with parentheses first.</u>

:\Longrightarrow \sf{x\cdot \:3x^2+x\left(-5x\right)+x\left(-10\right)+3\cdot \:3x^2+3\left(-5x\right)+3\left(-10\right)}

<u>Solve.</u>

\sf{x*3x=3x^3}

x(-5x)=-5x²

\sf{x(-10)=-10x}

3*3x²=9x²

3(-5x)=-15x

3(-10)=-30

<u>Then, rewrite the problem down.</u>

\sf{3x^3-5x^2-10x+9x^2-15x-30}

<u>Combine like terms.</u>

\Longrightarrow: \sf{3x^3-5x^2+9x^2-10x-15x-30}

<u>Add/subtract the numbers from left to right.</u>

-5x²+9x²=4x²

\Longrightarrow: \sf{3x^3+4x^2-10x-15x-30}

<u>Solve.</u>

\sf{-10x-15x=-25x}

<u>Then rewrite the problem.</u>

\Longrightarrow: \boxed{\sf{3x^3+4x^2-25x-30}}

  • <u>Therefore, the correct answer is 3x³+4x²-25x-30.</u>

I hope this helps! Let me know if you have any questions.

6 0
2 years ago
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Answer:

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Step-by-step explanation:

5 0
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I have a number between 60 and 80. I have a remainder of 3 when divided by 4. I have a remainder of 1 when divided by 7. What nu
Murljashka [212]

Answer:

71

Step-by-step explanation:

Divide 71 by 7 and you get 10 and 1 leftover. Divide 71 by 4 and you get 17 with 3 leftover.

6 0
2 years ago
Which two values of X are roots of the polynomial below 4x^2-6x+1
PtichkaEL [24]

4x^2-6x+1=0\\\\a=4,\ b=-6,\ c=1\\\\\Delta=b^2-4ac\\\\\Delta=(-6)^2-4(4)(1)=36-16=20\\\\\sqrt\Delta=\sqrt{20}=\sqrt{4\cdot5}=\sqrt4\cdot\sqrt5=2\sqrt5\\\\x_1=\dfrac{-b-\sqrt\Delta}{2a},\ x_2=\dfrac{-b+\sqrt\Delta}{2a}\\\\x_1=\dfrac{-(-6)-2\sqrt5}{2\cdot4}=\dfrac{3-\sqrt5}{4}\\\\x_2=\dfrac{-(-6)+2\sqrt5}{2\cdot4}=\dfrac{3+\sqrt5}{4}

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3 years ago
- 5x - 2y &lt;6<br> y &gt;-x+1
butalik [34]

Answer:

i dont know im only in 7th

Step-by-step explanation:

teehee

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