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insens350 [35]
2 years ago
8

From the set {30, 42, 84}, use substitution to determine which value of x makes the equation true.

Mathematics
1 answer:
Maru [420]2 years ago
8 0
2,520/x = 60
x = 42, which means your answer is B.

2,520/42 = 60
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Describe all of the transformations occurring as the parent function f(x) = x^3 is transformed into g(x) = -0.5(3(x+4))^3 -8
hodyreva [135]

Step-by-step explanation:

The translations of the typical functions are

y = a(bx + c)  + d

Where a is the vertical translation,

If a is greater than 1 or less than -1, we have a vertical stretch

If a is between -1 and 1 , we have a vertical compressions or shrink.

If a is negative, we have a negative reflection across the x axis.

If b is greater than 1 or less than -1, we have a horizontal compression or shrink

If b is between -1 and 1, we have a horizontal stretch

If b is negative, we have a reflection about the y axis,

If c is negative, we have a translation to the right c units

If c is positive, we have a translation to the left c units

If d is positive, we have a translation upward d units

If d is negative, we have a translation downward d units.

Here in this problem, our parent function is x^3.

So I would do the following transformations.

  • Reflect about the x axis
  • Vertical Shrink by a factor of 1/2
  • Horizontal Shrink by a factor of 3
  • Shift to the left 4 units
  • Shift downward 8 units.

4 0
2 years ago
Solve pls brainliest
Olenka [21]

Answer:

b

Step-by-step explanation:

I Think B is the right answer

5 0
2 years ago
I know I haven't been on this app for a long time but can ya'll help me plzz
nexus9112 [7]

Answer:

2774

Step-by-step explanation:

5 0
3 years ago
HEEELP
Drupady [299]

Answer: (c)

Step-by-step explanation:

Given

f(x)=\dfrac{1}{x-3}\\\\g(x)=\sqrt{x+5}

Here, \sqrt{x+5}\ \text{is always greater than equal to 0}\\\Rightarrow x+5\geq 0\\\Rightarrow x\geq -5\quad \ldots(i)

To get f\left(g(x)\right), replace x in f(x) by g(x)\ \text{i.e. by}\ \sqrt{x+5}

\Rightarrow f\left(g(x)\right)=\dfrac{1}{\sqrt{x+5}-3}\\\\\text{Denominator must not be equal to 0}\\\\\therefore \sqrt{x+5}-3\neq0\\\Rightarrow \sqrt{x+5}\neq 3\\\Rightarrow x+5\neq 9\\\Rightarrow x\neq 4\quad \ldots(ii)

Using (i) and (ii)  it can be concluded that the domain of f\left(g(x)\right) is all real numbers except 0.

Therefore, its domain is given by

x\in [-5,4)\cup (4,\infty)

Option (c) is correct.

5 0
3 years ago
Find the product 3 • ( -7 )
Vera_Pavlovna [14]

Answer:-21

Step-by-step explanation:

3•(-7)

3 x -7=-21

4 0
3 years ago
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