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Oliga [24]
1 year ago
15

Root 8-3 root 32 + 4 root 50 ​

Mathematics
1 answer:
Bess [88]1 year ago
3 0

Answer:

10\sqrt{2}

Step-by-step explanation:

\sqrt{8} -3\sqrt{32} +4\sqrt{50}

We can try to simplify first.

2\sqrt{2}-12\sqrt{2} +20\sqrt{2}

Now we can combine the like terms:

= 10\sqrt{2}

hope this helped! :)

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How do you understand what happens on a fraction number line and how do you know where the fraction is. Tell me how we will be a
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9514 1404 393

Answer:

  understand what the fraction means

Step-by-step explanation:

First of all, you need to <em>understand what 2/3 means</em>. It means 1 whole has been divided into 3 equal parts, and you're concerned with 2 of those parts.

In the number line in the first attachment, the space between 0 and 1 has been divided into 3 equal parts. The decimal value (rounded) is shown at each tick mark. The point marked "2/3" is located at the second of those divisions, counting from zero.

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The same fraction is located on the same number line in the second attachment. That number line is marked with divisions at intervals of 1/10, so there are 10 of them between 0 and 1. The value 2/3 is represented by the point that is (2/3)(10) = 6 2/3 of those intervals, so is between 0.6 and 0.7 on the number line.

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If the number line were divided into 12ths, then the fraction 2/3 would be located at the 8th tick mark, counting from 0. (2/3)(12) = 8 That is shown in the third attachment.

5 0
3 years ago
A sample of 10 adult elephants had an average weight of 12,556 pounds. The standard deviation
kirill [66]

Answer:

The 99% confidence interval of the population mean for the weights of adult elephants is between 12,475 pounds and 12,637 pounds.

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 10 - 1 = 9

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 9 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.99}{2} = 0.995. So we have T = 3.25

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M = T*s = 3.25*25 = 81

In which s is the standard deviation of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 12,556 - 81 = 12,475 pounds

The upper end of the interval is the sample mean added to M. So it is 12,556 + 81 = 12,637 pounds.

The 99% confidence interval of the population mean for the weights of adult elephants is between 12,475 pounds and 12,637 pounds.

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