Question

The area of a rectangle is 48 cm². If its width is 6 cm, what is its length?

Answer 1

Hey ! there

Answer:

• Length of rectangle is 8 cm .

Step-by-step explanation:

In this question we are provided with a rectangle having area 48 cm² and width 6 cm . We are asked to find the length of rectangle .

We know that ,

$\qquad \qquad\underline{\boxed{\frak{Area_{(Rectangle)} = l \times w}}}$

Where ,

• l refers to Length

• w refers to Width

SOLUTION : -

We are finding value of length by substituting value of width as 6 cm and area as 48 cm² in the formula . So ,

$\quad\longmapsto \qquad \:48 = 6 \times l$

or ,

$\quad\longmapsto \qquad \:48 = 6l$

Dividing with 6 on both sides :

$\quad\longmapsto \qquad \: \cancel{\dfrac{48}{6}} = \dfrac{ \cancel{6}l}{ \cancel{6}}$

We get ,

$\quad\longmapsto \qquad \: \orange{\underline{\boxed{ \frak{l = 8 \: cm}}}} \quad \bigstar$

• Henceforth , Length of rectangle having area 48 cm² and width 6 cm is ❝ 8 cm ❞

Verifying : -

We are verifying our answer by substituting value of length and width in formula and equating it with given area . So ,

• $8 \times 6 = 48$

• $48 = 48$

• $\rm{L.H.S = R.H.S}$

• $\rm{Hence , \: Verified .}$

Therefore , our answer is correct .

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Answer 2

AREA

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$\large \sf \underline{Question:}$

• The area of a rectangle is 48 cm². If its wdth is 6 cm, what is its length

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$\large \sf \underline{Answer:}$

$\qquad \qquad \qquad \huge \bold{8cm}$

To solve for the area of rectangle, you use this formula A = length × width. But we're doing it reversal, we will divide the width to the area

• $\large\tt{A \: = \: l \: \times \: w}$

• $\large\tt{48cm^{2} \: = \: l \: \times \: 6cm}$

• $\large\tt{48cm^{2} \: \div \: 6cm \: = \: l}$

• $\large\tt{48cm^{2} \: \div \: 6cm \: = \: \pmb{8cm}}$

Therefore, The length is 8cm.

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