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Papessa [141]
2 years ago
9

Rek is attending a four-year college. His tuition for one year derek is attending a four year college.his tuition for one year i

s $12,400 and his family is going to contribute $4,120.
w much does Derek need to save each month his junior and senior year of high school (two full years) to pay for the first year at
four-year college?
A. $516.67
B. $345.00
C. $172.50
D. $258.34
Mathematics
1 answer:
lara31 [8.8K]2 years ago
6 0
The correct answer is B.

The tuition is $12,400
His family pays $4,120
12,400 - 4,120= 8,280
8,280 divided by 24(months)= $345
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The first two terms in an arithmetic progression are -2 and 5. The last term in the progression is the only number in the progre
Rudik [331]

Given:

The first two terms in an arithmetic progression are -2 and 5.

The last term in the progression is the only number in the progression that is greater than 200.

To find:

The sum of all the terms in the progression.

Solution:

We have,

First term : a=-2

Common difference : d = 5 - (-2)

                                      = 5 + 2

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nth term of an A.P. is

a_n=a+(n-1)d

where, a is first term and d is common difference.

a_n=-2+(n-1)(7)

According to the equation, a_n>200.

-2+(n-1)(7)>200

(n-1)(7)>200+2

(n-1)(7)>202

Divide both sides by 7.

(n-1)>28.857

Add 1 on both sides.

n>29.857

So, least possible integer value is 30. It means, A.P. has 30 term.

Sum of n terms of an A.P. is

S_n=\dfrac{n}{2}[2a+(n-1)d]

Substituting n=30, a=-2 and d=7, we get

S_{30}=\dfrac{30}{2}[2(-2)+(30-1)7]

S_{30}=15[-4+(29)7]

S_{30}=15[-4+203]

S_{30}=15(199)

S_{30}=2985

Therefore, the sum of all the terms in the progression is 2985.

6 0
3 years ago
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Answer:

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