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Nimfa-mama [501]
2 years ago
9

What is the edge length of a cube with a volume of 27/64 cubic units?

Mathematics
2 answers:
Hunter-Best [27]2 years ago
6 0

Answer:

The length of the cube is 3/4 units.

Step-by-step explanation:

kicyunya [14]2 years ago
3 0

Answer:

3/8 unit

Step-by-step explanation:

\sqrt[3]{ \frac{27}{64} }  =  \frac{3}{8}

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Elena-2011 [213]
$9 + $7 + $5 = $21 so $18 - $21 = account balance = -$3
5 0
3 years ago
(×+2) +(4×-122)=180 need help with this problem
alina1380 [7]
So first you need to open the brackets, so it would be x+2+4x-122=180. Then we can add the 4x and the other x to make 5x, and then by doing 2-122 we get -120. This gives us the equation 5x-120=180. We then isolate the variable by moving the -120 to the other side of the equation and becoming a positive, so it would look like 5x=180+120. Then, we have 5x=300. 300 divides by 5 is 60 making X=60. Hope this helps!
6 0
3 years ago
I need help with this please. It’s probability.
Vinvika [58]

Answer:

2/13

Step-by-step explanation:

In a deck of 52 cards, there are 2 sets of red cards. Diamonds and Hearts. In each set of red cards, there are 4 fives. If there are 2 sets, that means that there are 8 red fives in the deck of 52 cards. This means that the probability is 8/52 which is simplified into 2/13.

8 0
4 years ago
Find the 14th term of the arithmetic sequence - 4x - 1, - 9x - 6 , -14x-11
Yanka [14]

Answer:

-69x-66

Step-by-step explanation:

1) given: a₁=-4x-1; a₂=-9x-6; a₃=-14x-11. Find: a₁₄-?

2) a₁₄=a₁+13d, where d - the difference between neighbor-terms;

3) d=a₂-a₁; ⇔ d= -9x-6+4x+1= -5x-5;

4) a₁₄= -4x-1+13*(-5x-5)= -69x-66.

3 0
3 years ago
Eugene noticed the temperature had dropped by 8 degrees from 17. What was the new temperature?
zubka84 [21]

Answer:

9 degrees

Step-by-step explanation:

given:

Initial temperature : 17 degrees

temperature change = reduction by 8 degrees (i.e - 8 degrees)

hence the final temperature

= initial temperature + temperature change

= 17 + (-8)

= 17 - 8

= 9 degrees

8 0
3 years ago
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