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spayn [35]
3 years ago
11

Help asap pls. Which of the following best describes how high and low pitch are different?

Physics
1 answer:
Gwar [14]3 years ago
3 0
Answer D. The pitch is in the frequency.
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What is a chemical energy
Papessa [141]

Chemical energy is the potential of a chemical substance to undergo a transformation through a chemical reaction to transform other chemical substances. Examples include batteries, food, gasoline, and etc.

8 0
3 years ago
How do you measure the amplitude of a longitudinal wave?
sp2606 [1]

You do it by the pressure difference it causes in the medium. Even in transversal waves, you usually need different units than meters because the wave has electric and magnetic vectors and not really any height to speak of.

you measure the amount of excursion from the equilibrium (no wave) level of whatever parameter is fluctuating.


3 0
4 years ago
The conductive tissues of the upper leg can be modeled as a 40-cm-long, 12-cm-diameter cylinder of muscle and fat. The resistivi
ahrayia [7]

To calculate and solve the problem it is necessary to apply the concepts related to resistance and resistivity.

The equation that is responsible for relating the two variables is:

R = \rho \frac{L}{A}

Where,

R= Resistance of the conductor

\rho =Resistivity of the conductor material

L = Length

A = Cross-sectional area of conductor

With the previous values the area of the muscle (Real Muscle-82%)is,

A_m = (0.82)\pi r^2 = (0.82)\pi (12/2*10^{-2})^2

A_m = 9.274*10^{-3}m^2

Using the equation from Resistance we have that at the muscle the value is:

R_m = \rho \frac{L}{A}

R_m = \frac{13*(0.4)}{9.274*10^{-3}}

R_m = 560.70\Omega

At the same time we can make the same process to calculate the resistance of the fat, then

A_m = (0.18)\pi r^2 = (0.18)\pi (12/2*10^{-2})^2

A_m = 2.0357*10^{-3}m^2

The resistance of the fat would be,

R_f = \rho \frac{L}{A}

R_f = \frac{25*(0.4)}{2.0357*10^{-3}}

R_f = 4912.3\Omega

Then the total resistance in a set as the previously writen, i.e, in parallel is:

R=\frac{R_mR_f}{R_m+R_f}

R = \frac{(560.70)(4912.3)}{4912.3+560.70}

R = 502.62\Omega

We can here apply Ohm's law, then

I= \frac{V}{R}

I = \frac{1.5}{502.62}

I = 2.984*10^{-3}A

I = 2.984mA

3 0
4 years ago
A machine part has the shape of a solid uniform sphere of mass 205 g and diameter 4.10 cm. It is spinning about a frictionless a
kondor19780726 [428]

Answer:

Answer is in the following attachment.

                                                                                                                                                                                                 

Explanation:

3 0
3 years ago
Can someone say for me ost right or wrong if it wrong say for me what is the answer plrase
saveliy_v [14]

Answer:

It is correct

Explanation:

8 0
3 years ago
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