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Oxana [17]
4 years ago
5

How did foucaults pendulum and coriolis effect are used to demonstrate earths tilt?

Physics
1 answer:
HACTEHA [7]4 years ago
7 0
They do not demonstrate Earth's tilt. In fact, they're not "used" to demonstrate anything. It works the other way:. When you observe the Coriolis effect and the behavior of the Foucault pendulum, and you try to explain why the behave the way they do, one possible simple explanation for both of them is the Earth's ROTATION. Then, when you also observe the rising and setting of the sun and moon, and you also notice how the NUMBERS all go together, the case for the rotating, spherical Earth gets stronger and stronger.
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w is last w

Explanation:

going diagonally to the left

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3 years ago
In Kevin study he knows that each participant has an equal probability of being placed into each of his conditions Kevin must ha
kodGreya [7K]

Answer:

Kevin must have used simple random sampling.

Explanation:

We can say that Kevin used simple random sampling. This is because this type of sampling allows elements to be taken from a population in a completely random way, to form a sample. In this case, each element, or individual, as shown in the question above, has the same probability of being selected to compose the sample, since this selection is completely random.

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2 years ago
What is the time period of vibration?
Y_Kistochka [10]

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4 0
3 years ago
Estimate the speed of the water free surface and the time required to fill with water a cone-shaped container 1.5 m high and 1.5
Zolol [24]

Answer:

speed of water is 0.0007138m/s

Explanation:

From the law of conservation of mass

Rate of mass accumulation inside vessel = mass flow in - mass flow out

so, dm/dt = mass flow in - mass flow out

taking p as density

d \frac{dQ}{dt} = pq_i_n

where,

q(in) is the volume flow rate coming in

Q = is the volume of liquid inside tank at any time

But,

dQ = Adh

where ,

A = area of liquid surface at time t

h = height from bottom at time t

A = πr²

r is the radius of liquid surface

r = (1.5/2) \div 1.5 h = \frac{h}{2}

Hence,

\pi( \frac{h}{2} )^2\frac{dh}{dt} =q_i_n

\frac{dh}{dt} = \frac{q_i_n}{\pi (\frac{h}{2})^2 } =\frac{4q_i_n}{\pi h^2}

so, the speed of water surface at height h

v = \frac{dh}{dt} =\frac{4q_i_n}{\pi h^2}

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Hence, speed of water is 0.0007138m/s

5 0
3 years ago
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