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4 years ago

What is the significance of the discovery of exoplanets?

Physics

2 answers:

polet [3.4K]4 years ago

5 0

For only through exploration of the unknown we have come as far as we are now.

Discoveries are what laid the foundation for the technology and all advancement of the society we have today. Similar to how we continue to voyage into the unknowns of this world to find resources to supply for our needs, studies through new materials, species we encounter will all benefit the most common problems we have such as energy resource, medical needs and cure for the incurable diseases. These explanetary exploration may be the next key which holds potential to solve these problems.

sveticcg [70]4 years ago

3 0

Sorry, i could not help you with the question, but I just wondering do you know what is Biomarker discovery.

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All points to the of zero on a horizontal number line are negative

Mumz [18]

Numbers on the left of zero are negative. Number lines go from smallest to greatest.

5 0

3 years ago

Read 2 more answers

(a) If the coefficient of kinetic friction between tires and dry pavement is 0.80, what is the shortest distance in which you ca

Colt1911 [192]

a) 52.5 m

b) 16.0 m/s

Explanation:

The motion of a car slowed down by friction is a uniformly accelerated motion, so we can use the following suvat equation:

$v^2-u^2=2as$

where

v = 0 is the final velocity (the car comes to a stop)

u = 28.7 m/s is the initial velocity of the car

a is the acceleration

s is the stopping distance

For a car acted upon the force of friction, the acceleration is given by the ratio between the force of friction and the mass of the car, so:

$a=\frac{-\mu mg}{m}=-\mu g$

where:

$\mu=0.80$ is the coefficient of friction

$g=9.8 m/s^2$ is the acceleration due to gravity

Substituting and solving for s, we find:

$s=\frac{v^2-u^2}{-2\mu g}=\frac{0-(28.7)^2}{-2(0.80)(9.8)}=52.5 m$

In this case, the car is moving on a wet road. Therefore, the coefficient of kinetic friction is

$\mu=0.25$

Here we want the stopping distance of the car to remain the same as part a), so

$s=52.5 m$

We can use again the same suvat equation:

$v^2-u^2=2as$

And since the final velocity is zero

u = 0

We can find the initial velocity of the car:

$v=\sqrt{2as}=\sqrt{2\mu gs}=\sqrt{2(0.25)(9.8)(52.5)}=16.0 m/s$

7 0

3 years ago

A 2 C charge and a 4 C charge attract each other with 10 N of force How much will a 2C charge and a 8 C charge attract each othe

densk [106]

Answer: 20N

Explanation:

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2 years ago

The wavelength of an electron whose velocity is 1.7 Ã 104 m/s and whose mass is 9.1 Ã 10-28 g is ________ m. the wavelength of a

madreJ [45]

<span>Mass of the electron = 9.1 x 10 ^ -28g = 9.1 x 10 ^ -31kg Velocity of the electron = 1.7 x 10 ^ 4 We have Planck Constant h = 6.626 x 10 ^ -34 Wavelength of the electron w = h/mv w = 6.626 x 10 ^ -34 / ((9.1 x 10 ^ -31)(1.7 x 10 ^ 4)) = 6.626 x 10 ^ -34 / 15.47 x 10 ^ -27 = 0.428312 x 10 ^ -7 = 4.28 x 10 ^ -8 m</span>

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3 years ago

J-s. If your 1400-kg car is parked in an 8.54-m-long garage, what is the uncertainty in its velocity? cm/s the tolerance is +/-2

IgorC [24]

Answer:

$\Delta v = 4.41 \times 10^{-37} cm/s$