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butalik [34]
2 years ago
10

Define what is false​

Physics
1 answer:
GalinKa [24]2 years ago
3 0

Answer: not according with truth or fact/ incorrect.

Explanation:

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Compare the time period of two simple pendulums of length 4m and 16m at a place.
Vlad1618 [11]

Answer:

the period of the 16 m pendulum is twice the period of the 4 m pendulum

Explanation:

Recall that the period (T) of a pendulum of length (L)  is defined as:

T=2\,\pi\,\sqrt{ \frac{L}{g} }

where "g" is the local acceleration of gravity.

SInce both pendulums are at the same place, "g" is the same for both, and when we compare the two periods, we get:

T_1=2\,\pi\,\sqrt{\frac{4}{g} } \\T_2=2\,\pi\,\sqrt{\frac{16}{g} } \\ \\\frac{T_2}{T_1} =\sqrt{\frac{16}{4} } =2

therefore the period of the 16 m pendulum is twice the period of the 4 m pendulum.

5 0
2 years ago
A car is traveling 100 km/hr. How many hours will it take to cover a distance of 850 km?
Evgesh-ka [11]

Answer:

8.5 hours

Explanation:

7 0
3 years ago
Read 2 more answers
If you drop an object from a height of 1.9 m, it will hit the ground in 0.62 s. if you throw a baseball horizontally with an ini
faltersainse [42]
That's the cool thing about free fall.  The amount of time it takes to fall remains the same.

In this case, a ball that is simply dropped from rest will fall at the same rate as a ball that had some umph in the horizontal direction.

6 0
3 years ago
people will buy more of a good when its price falls and less when its price rises, according to the....
Svetlanka [38]
People will buy more of a good when its price falls and less when its price rises, according to the law of demand. 
5 0
2 years ago
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A photon with an energy E = 2.12 GeV creates a proton-antiproton pair in which the proton has a kinetic energy of 96.0 MeV. What
Oksanka [162]

Answer:

The kinetic energy of the anti proton is 147.4 MeV.

Explanation:

Given that,

Energy = 2.12 GeV

Kinetic energy = 96.0 MeV

We need to calculate the kinetic energy of the anti proton

Using formula of energy

E_{photon}=m_{p}c^2+m_{np}c^2+K.E_{p}+K.E_{np}

We know that,

m_{p}c^2=m_{np}c^2

So, E_{photon}=2mc^2+K.E_{p}+K.E_{np}

K.E_{np}=E_{photon}-(2mc^2+K.E_{p})

Put the value into the formula

K.E_{np}=2.12\times10^{9}-2\times938.3\times10^{6}-96\times10^{6}

K.E_{np}=147.4\ MeV

Hence, The kinetic energy of the anti proton is 147.4 MeV.

6 0
2 years ago
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