Answer:
The charges under study are of the same sign
The calculation of the electric field for each charge separately, there is no relationship between the charges
Explanation:
Let's start by writing the equation for the electric field
E = k q / r²
where q is the charge under analysis and r the distance from this charge to a positive test charge.
When analyzing the statement the student has some problems.
* The charges under study are of the same sign, it does not matter if positive or negative.
* The calculation of the electric field for each charge separately, there is no relationship between the charges for the calculation of the electric field.
* What is added is the interaction of the electric field with the positive test charge, in this case each field has the opposite direction to the other, so the vector sum gives zero
Answer:
6.0cm
Explanation:
Given
focal length = 15.0cm
object distance = 10.0cm
Required
Image distance v
Using the formula
1/f = 1/u + 1/v
1/15 = 1/10+1/v
1/v = 1/15 + 1/10
1/v = 2+3/30
1/v = 5/30
v = 30/5
v = 6.0cm
Hence the image distance is 6.0cm
Answer:
d
Explanation:
and just because trust me on this one my guy
