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mario62 [17]
2 years ago
14

Which scientific law states the relationship between an object's mass, acceleration, and amount of force acting on it? (3 points

)
1. Law of universal gravitation
2. Newton's third law of motion
3. Keplar's law of planetary motion
4. Newton's second law of motion
Physics
2 answers:
Ksenya-84 [330]2 years ago
7 0

Answer:

number 2

Explanation:

Newton's second law of motion can be formally stated as follows: The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.

Kisachek [45]2 years ago
4 0

Answer:

4.Newton's second law of motion

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An infinitely long straight wire has a uniform linear charge density of Derive the 4. equation for the electric field a distance
marshall27 [118]

Answer:

E = \frac{\lambda}{2\pi \epsilon_0 r}

Explanation:

Let the linear charge density of the charged wire is given as

\frac{q}{L} = \lambda

here we can use Gauss law to find the electric field at a distance r from wire

so here we will assume a Gaussian surface of cylinder shape around the wire

so we have

\int E. dA = \frac{q}{\epsilon_0}

here we have

E \int dA = \frac{\lambda L}{\epsilon_0}

E. 2\pi r L = \frac{\lambda L}{\epsilon_0}

so we have

E = \frac{\lambda}{2\pi \epsilon_0 r}

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3 years ago
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Gelneren [198K]

Answer:

C

Explanation:

8 0
3 years ago
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Answer:

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2 years ago
A myopic person (assume no astigmatism) is diagnosed with a far point of 160 cm. What corrective prescription should they be sup
Kazeer [188]

Answer:

The person should use a convex lens of power -0.625 D.

Explanation:

Given that, the far point of the person, with myopic eye, is 160 cm.

It means that the image of an object, which is at infinity, is formed at this point 160 cm distance away from the person's eye.

If the object is infinity, then the object distance, u = -\infty.

Image distance, v = -160 cm.

u and v are taken to be negative because the object and the image of the object are on the side of the eye from where the light is coming.

Let the focal length of the lens which is to be used for the correction of this myopic eye be f, then using lens equation,

\rm \dfrac 1f = \dfrac 1v-\dfrac 1u=\dfrac 1{-160 }-\dfrac1{-\infty}=\dfrac 1{-160}-0=\dfrac 1{-160}.\\\Rightarrow f=-160\ cm.

The negative focal length indicates that the lens should be convex.

The power of the lens is given by

\rm P=\dfrac{1}{f}=\dfrac{1}{-160\ cm }=\dfrac{1}{-1.6\ m}=-0.625\ D.

So, the person should use a convex lens of power -0.625 D.

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Answer:40m/s

Explanation:2400/60

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