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umka21 [38]
3 years ago
12

(1)/(2)(8y-4)=(3)/(4)(16-8y)

Mathematics
1 answer:
Talja [164]3 years ago
7 0

Answer:   y=7/5

Hope this helps

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3x²=12 extracting square roots​
ivann1987 [24]

Answer:

x = ± 2

Step-by-step explanation:

Given

3x² = 12 ( divide both sides by 3 )

x² = 4 ( take the square root of both sides )

x = ± \sqrt{4} = ± 2

3 0
3 years ago
PHYSICS As a ray of light meets a mirror, the light
Lady bird [3.3K]
<h3>Answer:  37 degrees</h3>

========================================================

Explanation:

The angle of incidence is equal to the angle of reflection. The angle of light coming in is the same as the angle of light bouncing out. Each angle is made with the dashed line as the diagram shows.

So angle RMI = 106 is bisected, i.e. divided in half, to get

  • Angle RMN = 53
  • Angle NMI = 53

since 106/2 = 53

Then notice that the horizontal dashed line is perpendicular to the vertical mirror. This means angle NMJ is a 90 degree angle and,

angle RMJ = (angle NMJ) - (angle RMN)

angle RMJ = 90 - 53

angle RMJ = 37 degrees

----------

In short: divide 106 in half to get 53, then subtract it from 90

5 0
2 years ago
PLEASE I NEED HELP WITH THIS
Ber [7]

Given:

The figure of a circle.

To find:

The measure of arc AD and measure of each arc.

Solution:

The measure of arc is equal to the central angle of that arc.

The central angle of arc AD is 105 degrees. So,

m(arc(AD))=105^\circ

The central angle of arc BC is 35 degrees. So,

m(arc(BC))=35^\circ

The central angle of arc CD is 50 degrees. So,

m(arc(CD))=50^\circ

The central angle of a complete circle is 360 degrees. So,

m(arc(AD))+m(arc(BC))+m(arc(CD))+m(arc(AB))=360^\circ

105^\circ+35^\circ+50^\circ+m(arc(AB))=360^\circ

190^\circ+m(arc(AB))=360^\circ

m(arc(AB))=360^\circ-190^\circ

m(arc(AB))=170^\circ

Therefore, the measure of arc AD is 105°, the measure of arc BC is 35°, the measure of arc CD is 50° and the measure of arc AB is 170°

3 0
3 years ago
Please answer the following question
Arte-miy333 [17]
Yeah there all right but I have a little hinch for the last and first one
6 0
4 years ago
It would be great if someone could help me with this problem
GaryK [48]
Y-intercept (0, 1)
Equation of asymptote y=0

Equation of asymptote can also be called horizontal asymptote.
It means the place where the line almost meets but actually not touching the place. The line almost touches y=0 but it actually does not touch it.

7 0
3 years ago
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