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3 years ago

I need help on questions 2 please and thank you

Mathematics

1 answer:

EleoNora [17]3 years ago

8 0

I would say B , even though I’m only in 5 th grade

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Put the equation below in the form ax2 + bx + c = 0. Enter exponents using the caret ( ^ ). For example, you would enter 4x2 as

Ymorist [56]

X2+ 4x + 7 = 0 is the correct answer

4 0

3 years ago

Please give me the correct answer!!!

Neko [114]

Answer:

Step-by-step explanation:

this one is tricky so b/c the lines are at 90 degees we know that the arcs are similar so set up the parts of the arcs equal to 360 degrees

360 = 130 + 130 + x + x

see each part of the circle ?

then use your mad algebra skilz

100 = 2x

50 = x

:) nice.. when I do the math , it seems easy , huh :DDD

7 0

2 years ago

Worth 15 points please answer asap!!!!

ExtremeBDS [4]

So do the opposite of the answer like for example 4 +3\2 and your answer is y
the you do the rest

6 0

3 years ago

Help me please i don't know what to do

astra-53 [7]

Answer:

a. a = 1, b = -5, c = -14

b. a = 1, b = -6, c = 9

c. a = -1, b = -1, c = -3

d. a = 1, b = 0, c = -1

e. a = 1, b = 0, c = -3

Step-by-step explanation:

a. x-ints at 7 and -2

this means that our quadratic equation must factor to:

$(x-7)(x+2) = 0$

FOIL:

$x^2 + 2x - 7x - 14 = 0$

Simplify:

$x^2 - 5x - 14 = 0$

a = 1, b = -5, c = -14

b. one x-int at 3

this means that the equation will factor to:

$(x-3)^2=0$

FOIL:

$x^2 - 3x - 3x +9 = 0$

Simplify:

$x^2 - 6x + 9 = 0$

a = 1, b = -6, c = 9

c. no x-int and negative y must be less than 0

This means that our vertex must be below the x-axis and our parabola must point down

There are many equations for this, but one could be:

$-x^2-x-3=0$

a = -1, b = -1, c = -3

d. one positive x-int, one negative x-int

We can use any x-intercepts, so let's just use -1 and 1

The equation will factor to:

$(x+1)(x-1)=0$

This is a perfect square

FOIL:

$x^2-1=0$

a = 1, b = 0, c = -1

e. x-int at $\sqrt{3} , -\sqrt{3}$

our equation will factor to:

$(x+\sqrt{3} )(x-\sqrt{3)} =0$

This is also a perfect square

FOIL and you will get:

$x^2 - 3 = 0$

a = 1, b = 0, c = -3

4 0

1 year ago

Determine the angles made by the vector v = (67)i + (-15)j with the positive x- and y-axes. write the unit vector n in the direc

vivado [14]

Consider the picture attached.

From right triangle trigonometry:

tan(α)=(opposite side)/(adjacent side)=15/67=0.2239

using a scientific calculator we find that arctan(0.2239)=12.62°

thus α=12.62°, is the angle that the vector makes with the positive x-axis.

The angle made with the + y-axis is 12.62°+90°=102.62°.

The length of the vector v can be determined using the Pythagorean theorem:

$|v|= \sqrt{ 67^{2} + 15^{2} }= \sqrt{4489+225}= \sqrt{4714}=68.8$

Thus, to make v a unit vector, without changing its direction, we need to divide v by |v|=68.8.

This means that the x and y components will also be divided by 68.8, by proportionality.

So, the unit vector in the direction of v is:

<span>(67/68.8)i + (-15/68.8)j=0.97 i + (- 0.22)j
</span>

Answer: 12.62°; 102.62°; 0.97 i + (- 0.22)j

6 0

3 years ago