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Salsk061 [2.6K]
2 years ago
6

Please solve the inequality and give the steps needed to solve: x²-13x+36 ≤ 0

Mathematics
1 answer:
Svetlanka [38]2 years ago
6 0
I hope y’all have a good day!!
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At the beginning of an experiment, the temperature of a solution was 48°C. During a 6-hour
ExtremeBDS [4]

9514 1404 393

Answer:

  • -2.2(6) +1.8(4) . . . temperature change
  • 42 °C

Step-by-step explanation:

At the end of the first 6 hours, the temperature change was ...

  (-2.2 K/h)(6 h) = -13.2 K

The change in the next 4 hours was ...

  (1.8 K/h)(4 h) = 7.2 K

Then the total change over the 10-hour period was ...

  (-2.2)(6) +(1.8)(4) . . . . . expression for temperature change

This evaluates to -13.2 +7.2 = -6.

__

The final temperature is the sum of the initial temperature and the temperature change:

  final temperature = 48 °C -6 °C = 42 °C

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<em>Additional comment</em>

When temperature is measured on the Celsius scale, a change of 1 degree is called a kelvin (K).

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Step-by-step explanation:

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M is the midpoint of AN, A has coordinates
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Step-by-step explanation:

According to Question , M is the midpoint of AN, A has coordinates (-7,4), and M has coordinates (-4, -1).

<u>Figure</u><u> </u><u>:</u><u>-</u>

\setlength{\unitlength}{1 cm}\begin{picture}(20,12) \put(4,0.2){\line(0,-1){0.4}}\put(1,0){\line(1,0){6}} \put(3.8,-0.6){$\bf M(-4,-1) $} \put(1,-0.6){$\bf A (-7,4)$}   \put(6.8,-0.6){$\bf N(x,y)$} \end{picture}

Let the coordinates of N be ( x , y )

Now , according to Midpoint Formula , the midpoint of points say A(x , y) and B (x' , y') is given by ,

\boxed{\blue{ \bf Midpoint =\bigg( \dfrac{x+x'}{2} , \dfrac{y+y'}{2} \bigg) }}

<u>On</u><u> </u><u>using</u><u> </u><u>this</u><u> </u><u>formula</u><u> </u><u>,</u><u> </u>

=> Midpoint = \bigg( \dfrac{x+x'}{2} , \dfrac{y+y'}{2} \bigg)  \\ \\ => (-4, 1) = \bigg( \dfrac{x -7 }{2} , \dfrac{y + 4 }{2}\bigg) \\ \\ => -4 = \dfrac{x-7}{2} \\\\ => x - 7 = -8 \\\\ => x = 7 -8 \\\\ \boxed{\red{\sf=> x = -1 }} \\\\ => \dfrac{y+4}{2}=-1 \\\\=> y +4 = -2 \\ \\ y = -4-2 \\\\\boxed{\red{\sf=> y = -6 }}

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